大家帮小弟我看一下这段代码吧

大家帮我看一下这段代码吧
#   include   "stdio.h "  
#   include   "conio.h "  

void   shi();  
void   cal();  

main()  
{char   c;  

do  
{  
printf( "****************************************\n\n\n\n ");  
printf( "   1.   Calcullator\n ");  
printf( "   2.   Biao   da   shi\n ");  
printf( "\n\n\n\n****************************************\n ");  
printf( "\n\n\n\n\n\nplease   input   you   choice   the   number:\n ");  
c=getchar();  
if(c== '1 ')cal();  
if(c== '2 ')shi();  
printf( "please   choice   the   number   again\n ");  
}while(c!= '1 '&&c!= '2 ');  
}  


大家帮我看一下这段代码吧，我有点不明白中间的
printf( "****************************************\n\n\n\n ");  
printf( "   1.   Calcullator\n ");  
printf( "   2.   Biao   da   shi\n ");  
printf( "\n\n\n\n****************************************\n ");  
printf( "\n\n\n\n\n\nplease   input   you   choice   the   number:\n ");  

这段是干什么的

printf( "****************************************\n\n\n\n ");  
printf( "   1.   Calcullator\n ");  
printf( "   2.   Biao   da   shi\n ");  
printf( "\n\n\n\n****************************************\n ");  

这四句去掉行吗

------解决方案--------------------
printf( "****************************************\n\n\n\n "); //这是输出一排星号
printf( " 1. Calcullator\n "); //为的是美观,没什么用
printf( " 2. Biao da shi\n ");
printf( "\n\n\n\n****************************************\n ");
printf( "\n\n\n\n\n\nplease input you choice the number:\n "); //这输出一堆回车
//再输出一句话,用来提示用户如何操作
这段是干什么的

printf( "****************************************\n\n\n\n "); //这都是个美观的作用
printf( " 1. Calcullator\n "); //楼主完全可以删之
printf( " 2. Biao da shi\n ");
printf( "\n\n\n\n****************************************\n ");