ORACLE中怎么根据条件拆分一个字符串字段为2个数值字段

ORACLE中如何根据条件拆分一个字符串字段为2个数值字段？

SQL code


--oracle10g
create table BREAKOUT
(
  OBJECTID     INTEGER not null,
  GJ           NVARCHAR2(10),
  RWIDTH       NUMBER(38,8),
  RHEIGHT      NUMBER(38,8)
);

insert into BREAKOUT (OBJECTID,GJ,Rwidth,Rheight) values (1,'500X600',0,0);
insert into BREAKOUT (OBJECTID,GJ,Rwidth,Rheight) values (2,'700X600',0,0);
insert into BREAKOUT (OBJECTID,GJ,Rwidth,Rheight) values (3,'300X400',0,0);
insert into BREAKOUT (OBJECTID,GJ,Rwidth,Rheight) values (4,'450',0,0);
insert into BREAKOUT (OBJECTID,GJ,Rwidth,Rheight) values (4,'550',0,0);

select * from BREAKOUT;

我想把GJ这个字段，拆成2个数值，第一个数值放在RWIDTH里边，第二个数值放在RHEIGHT里边;而且，如果没有X的话，默认放到RWIDTH里边，请问，该怎么写UPDATE语句呢？

------解决方案--------------------

SQL code


update BREAKOUT
   set RWIDTH = (case when instr(GJ, 'X') > 0 then to_number(substr(GJ, 1, instr(GJ, 'X') - 1)) else to_number(GJ) end),
       RHEIGHT =(case when instr(GJ, 'X') > 0 then to_number(substr(GJ, instr(GJ, 'X') + 1)) else RHEIGHT end);
commit;

ORACLE中怎么根据条件拆分一个字符串字段为2个数值字段

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