SQL中删除表内的重复数据,该怎么处理
SQL中删除表内的重复数据
表是用于保存修改的历史记录的, 表的结构如下:
TABLE [dbo].[Upd_Record](
[ID] [decimal](18, 0) IDENTITY(1,1) NOT NULL, --标识列
[Table_nm] [varchar](50) NOT NULL,--外联表名
[Table_Cell] [varchar](50) NOT NULL,--单元格名称
[Row_ID] [decimal](18, 0) NOT NULL,--外联主键
[Cell_Value] [decimal](18, 4) NULL,--值 ,主要是这个重复
[upd_date] [datetime] NOT NULL,--修改日期
[upd_id] [decimal](18, 0) NULL--修改人
数据例子如下:
id Table_nm Table_Cell Row_ID Cell_Value
1 bxsphz_sub clf 327 564.0000 2012-03-23 14:34:46.000 4195
2 bxsphz_sub bxywf 327 495.0000 2012-03-23 14:34:46.000 4195
3 bxsphz_sub tmoney 327 0.0000 2012-03-23 14:34:46.000 4195
4 bxsphz_sub clf 327 564.0000 2012-03-25 14:21:35.000 2121
5 bxsphz_sub bxywf 327 495.0000 2012-03-25 14:21:35.000 2121
6 bxsphz_sub tmoney 327 0.0000 2012-03-25 14:21:35.000 2121
需求如下:
如果有修改的数据,保留;
如果2次修改没有改变过数据, 则只保留最早的,如上面的数据 应保留123,删除456;
由于修改日期基本上是越来越大的,所以按照ID大小来删除应该就可以了, 于是LZ写了如下的 sql语句:
select * from Upd_Record
where ID not in(
select g.ID
from Upd_Record g
where exists (
select f.ID
from Upd_Record f
where f.ID < g.ID and not exists (
select Table_nm, Table_Cell, Row_ID, Cell_Value
from Upd_Record
where ID = f.ID or ID = g.ID
group by Table_nm, Table_Cell, Row_ID, Cell_Value
having count(*) =1)))
go
用临时表测试的时候,感觉这个应该是可行的,但是复制到数据表中, 由于数据有 45W多条,卡住了10来分钟仍然在查询中,无法得到结果。
因此特来求教, 有没有一些好的办法来处理 删除重复的数据这样的需求?尤其是大批量的时候
------解决方案--------------------
表是用于保存修改的历史记录的, 表的结构如下:
TABLE [dbo].[Upd_Record](
[ID] [decimal](18, 0) IDENTITY(1,1) NOT NULL, --标识列
[Table_nm] [varchar](50) NOT NULL,--外联表名
[Table_Cell] [varchar](50) NOT NULL,--单元格名称
[Row_ID] [decimal](18, 0) NOT NULL,--外联主键
[Cell_Value] [decimal](18, 4) NULL,--值 ,主要是这个重复
[upd_date] [datetime] NOT NULL,--修改日期
[upd_id] [decimal](18, 0) NULL--修改人
数据例子如下:
id Table_nm Table_Cell Row_ID Cell_Value
1 bxsphz_sub clf 327 564.0000 2012-03-23 14:34:46.000 4195
2 bxsphz_sub bxywf 327 495.0000 2012-03-23 14:34:46.000 4195
3 bxsphz_sub tmoney 327 0.0000 2012-03-23 14:34:46.000 4195
4 bxsphz_sub clf 327 564.0000 2012-03-25 14:21:35.000 2121
5 bxsphz_sub bxywf 327 495.0000 2012-03-25 14:21:35.000 2121
6 bxsphz_sub tmoney 327 0.0000 2012-03-25 14:21:35.000 2121
需求如下:
如果有修改的数据,保留;
如果2次修改没有改变过数据, 则只保留最早的,如上面的数据 应保留123,删除456;
由于修改日期基本上是越来越大的,所以按照ID大小来删除应该就可以了, 于是LZ写了如下的 sql语句:
select * from Upd_Record
where ID not in(
select g.ID
from Upd_Record g
where exists (
select f.ID
from Upd_Record f
where f.ID < g.ID and not exists (
select Table_nm, Table_Cell, Row_ID, Cell_Value
from Upd_Record
where ID = f.ID or ID = g.ID
group by Table_nm, Table_Cell, Row_ID, Cell_Value
having count(*) =1)))
go
用临时表测试的时候,感觉这个应该是可行的,但是复制到数据表中, 由于数据有 45W多条,卡住了10来分钟仍然在查询中,无法得到结果。
因此特来求教, 有没有一些好的办法来处理 删除重复的数据这样的需求?尤其是大批量的时候
------解决方案--------------------
- SQL code
删除重复记录有大小关系时,保留大或小其中一个记录 --> --> (Roy)生成測試數據 if not object_id('Tempdb..#T') is null drop table #T Go Create table #T([ID] int,[Name] nvarchar(1),[Memo] nvarchar(2)) Insert #T select 1,N'A',N'A1' union all select 2,N'A',N'A2' union all select 3,N'A',N'A3' union all select 4,N'B',N'B1' union all select 5,N'B',N'B2' Go --I、Name相同ID最小的记录(推荐用1,2,3),保留最小一条 方法1: delete a from #T a where exists(select 1 from #T where Name=a.Name and ID<a.ID) 方法2: delete a from #T a left join (select min(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID where b.Id is null 方法3: delete a from #T a where ID not in (select min(ID) from #T where Name=a.Name) 方法4(注:ID为唯一时可用): delete a from #T a where ID not in(select min(ID)from #T group by Name) 方法5: delete a from #T a where (select count(1) from #T where Name=a.Name and ID<a.ID)>0 方法6: delete a from #T a where ID<>(select top 1 ID from #T where Name=a.name order by ID) 方法7: delete a from #T a where ID>any(select ID from #T where Name=a.Name) select * from #T 生成结果: /* ID Name Memo ----------- ---- ---- 1 A A1 4 B B1 (2 行受影响) */ --II、Name相同ID保留最大的一条记录: 方法1: delete a from #T a where exists(select 1 from #T where Name=a.Name and ID>a.ID) 方法2: delete a from #T a left join (select max(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID where b.Id is null 方法3: delete a from #T a where ID not in (select max(ID) from #T where Name=a.Name) 方法4(注:ID为唯一时可用): delete a from #T a where ID not in(select max(ID)from #T group by Name) 方法5: delete a from #T a where (select count(1) from #T where Name=a.Name and ID>a.ID)>0 方法6: delete a from #T a where ID<>(select top 1 ID from #T where Name=a.name order by ID desc) 方法7: delete a from #T a where ID<any(select ID from #T where Name=a.Name) select * from #T /* ID Name Memo ----------- ---- ---- 3 A A3 5 B B2 (2 行受影响) */ --3、删除重复记录没有大小关系时,处理重复值 --> --> (Roy)生成測試數據 if not object_id('Tempdb..#T') is null drop table #T Go Create table #T([Num] int,[Name] nvarchar(1)) Insert #T select 1,N'A' union all select 1,N'A' union all select 1,N'A' union all select 2,N'B' union all select 2,N'B' Go 方法1: if object_id('Tempdb..#') is not null drop table # Select distinct * into # from #T--排除重复记录结果集生成临时表# truncate table #T--清空表 insert #T select * from # --把临时表#插入到表#T中 --查看结果 select * from #T /* Num Name ----------- ---- 1 A 2 B (2 行受影响) */ --重新执行测试数据后用方法2 方法2: alter table #T add ID int identity--新增标识列 go delete a from #T a where exists(select 1 from #T where Num=a.Num and Name=a.Name and ID>a.ID)--只保留一条记录 go alter table #T drop column ID--删除标识列 --查看结果 select * from #T /* Num Name ----------- ---- 1 A 2 B (2 行受影响) */ --重新执行测试数据后用方法3 方法3: declare Roy_Cursor cursor local for select count(1)-1,Num,Name from #T group by Num,Name having count(1)>1 declare @con int,@Num int,@Name nvarchar(1) open Roy_Cursor fetch next from Roy_Cursor into @con,@Num,@Name while @@Fetch_status=0 begin set rowcount @con; delete #T where Num=@Num and Name=@Name set rowcount 0; fetch next from Roy_Cursor into @con,@Num,@Name end close Roy_Cursor deallocate Roy_Cursor --查看结果 select * from #T /* Num Name ----------- ---- 1 A 2 B (2 行受影响) */ 方法太多了,随便选一种吧