算法!用C#写一个函数,在一个数组中找到随意几个值相加等于一个值
算法!用C#写一个函数,在一个数组中找出随意几个值相加等于一个值
比如,数组{1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19}
要找出那些数相加等于20,
请各位大侠不吝赐教,谢谢
------解决方案--------------------
int[] myarray = { 1, 2,3,4,5,6,7,8,9,10,11 };
List<List<int>> mylist = new List<List<int>>();
int length = myarray.Length;
for (int i = 0; i < Math.Pow(2, length); i++)
{
List<int> myint = new List<int>();
for (int j = 0; j < length; j++)
{
if (Convert.ToBoolean(i & (1 << j)))
myint.Add(myarray[j]);
}
mylist.Add(myint);
}
foreach (var a in mylist)
{
if (a.Sum() == 20)
{
foreach (var b in a)
{
Console.Write(b); Console.Write(",");
}
Console.WriteLine();
}
------解决方案--------------------
给你写个例子:
比如,数组{1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19}
要找出那些数相加等于20,
请各位大侠不吝赐教,谢谢
------解决方案--------------------
int[] myarray = { 1, 2,3,4,5,6,7,8,9,10,11 };
List<List<int>> mylist = new List<List<int>>();
int length = myarray.Length;
for (int i = 0; i < Math.Pow(2, length); i++)
{
List<int> myint = new List<int>();
for (int j = 0; j < length; j++)
{
if (Convert.ToBoolean(i & (1 << j)))
myint.Add(myarray[j]);
}
mylist.Add(myint);
}
foreach (var a in mylist)
{
if (a.Sum() == 20)
{
foreach (var b in a)
{
Console.Write(b); Console.Write(",");
}
Console.WriteLine();
}
------解决方案--------------------
给你写个例子:
- C# code
using System; using System.Collections.Generic; using System.Linq; namespace ConsoleApplication1 { class Program { static void Main(string[] args) { double[] myarray = { 1.1, 2.5, 3.3, 4.9, 5.8, 6.8, 7.5, 8.7, 9.4, 10.7, 11.2, 12.9, 13.6, 14.8, 15.9, 16.4, 17.7, 18.4, 19.2 }; int cnt = 0; foreach (var result in 寻找组合(myarray, 50.8, myarray.Length - 1)) { Console.Write("结果{0}==> ", ++cnt); foreach (var n in result) Console.Write("{0} ", n); Console.WriteLine(); } Console.WriteLine("--------------End"); Console.ReadKey(); } static IEnumerable<IEnumerable<double>> 寻找组合(double[] array, double sum, int index) { if (index >= 0) { foreach (var sub in 寻找组合(array, sum, index - 1)) yield return sub; foreach (var sub in 寻找组合(array, sum - array[index], index - 1)) yield return sub.Concat(new double[] { array[index] }); if (Math.Abs(array[index] - sum) <= double.Epsilon) yield return new double[] { array[index] }; } } } }
------解决方案--------------------