回想法——Ural 1073 Square Country
回溯法——Ural 1073 Square Country

1073. Square Country
Time Limit: 1.0 second
Memory Limit: 16 MB
Memory Limit: 16 MB
There live square people in a square country. Everything in this country is square also. Thus, the Square Parliament has passed a law about a land. According to the law each citizen of the country has
a right to buy land. A land is sold in squares, surely. Moreover, a length of a square side must be a positive integer amount of meters. Buying a square of land with a side a one pays a2 quadrics
(a local currency) and gets a square certificate of a landowner.
One citizen of the country has decided to invest all of his N quadrics into the land. He can, surely, do it, buying square pieces 1 × 1 meters. At the same time the citizen has requested to
minimize an amount of pieces he buys: "It will be easier for me to pay taxes," — he has said. He has bought the land successfully.
Your task is to find out a number of certificates he has gotten.
Input
The only line contains a positive integer N ≤ 60 000 , that is a number of quadrics that the citizen has invested.
Output
The only line contains a number of certificates that he has gotten.
Sample
input | output |
---|---|
344 |
3 |
搜索过程图示
#include <iostream> #include <cstdio> #include <cstring> #include <cmath> using namespace std; #define MAX 250 int minn; //最小数量 int ConstructCandidates(int *c, int r) { int f = (int)sqrt((double)r); int i; for (i = 0; f > 0; i++, f--) { c[i] = f; } return i; } bool Backtrack(int k, int r) { if (r == 0) { if (k < minn) { minn = k; } } else { int c[MAX]; int nc = ConstructCandidates(c, r); int i; for (i = 0; i < nc; i++) { if (k+1 < minn) { if (!Backtrack(k+1, r-(c[i]*c[i]))) { return true; //结束本层 } } else { return false; //本层所有候选值都不会产生更优解 } } } return true; } int main(void) { int n; while (scanf("%d", &n) != EOF) { minn = 99999999; Backtrack(0, n); printf("%d\n", minn); } return 0; }