在php中将字符串转换为整数时返回零

问题描述：

when I want to convert a numeric string variable into integer in php, the return value is zero. I used all ways to convert it! such as:(int), (integer), intval(), settype(), eval(), etc. all of them return zero!

var_dump($myVariable) prints the following:

string(4) "۲۹"

当我想在php中将数字字符串变量转换为整数时，返回值为零。我用各种方法来转换它！例如：（int），（整数），intval（），settype（），eval（）等等都返回零！ p>

var_dump（$ myVariable） code>打印以下内容： p>

  string（4）“29”
   code>  pre> 
  div>

答

I found it! before converting string to integer, I should convert arabic number to english using this function:

function convert($string) {
$persian = array('۰', '۱', '۲', '۳', '۴', '۵', '۶', '۷', '۸', '۹');
$num = range(0, 9);
return str_replace($persian, $num, $string);
}

now, I can convert it! thanks from kingkero.

答

Other common error is trying to cast a string variable that contains numbers but starts with zero, i.e.:

string(5) " 358"

To solve this, I used a filter_var sanitizing number INT doing this:

$myVariable = filter_var($myVariable, FILTER_SANITIZE_NUMBER_INT);

在php中将字符串转换为整数时返回零

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