求struts2.0时间比较的步骤

求struts2.0时间比较的方法？

http://www.iteye.com/problems/54472求struts2.0时间比较的方法？这个问题，可以很简单的实现，是用xxq 的方法

<s:iterator value="zbgsList" status="status">
        <dl <s:if test="#status.index%2==0">class='fff'</s:if>>
         <dt>
         <a href="#">
         <s:if test="ftitle.length()>29">         
              <s:property value="ftitle.substring(0,29)"/>…
            </s:if>                  
            <s:else>      
              <s:property value="ftitle"/>  
            </s:else>
         </a>
         <%
         request.setAttribute("defaultTime", new java.util.Date().getTime()/24/3600/1000);
         Date ddd=(Date)request.getAttribute("defDate1");
         request.setAttribute("lessTime",ddd.getTime()/24/3600/1000);
         %>
         <s:if test ="((#request.defaultTime-#request.lessTime))<=3">
         <img src='images/new01.gif' align='middle'/>
         </s:if>
        </dt>
        <dd ><s:date  name="defDate1" format="yyyy-MM-dd HH:hh:ss"/>
        </dd>
        </dl>
        </s:iterator>