Python初学者第六天 列表操作练习

6day

列表练习:

1、创建一个空列表,命名为names,往里面添加old_drilver,rain,jack,shanshan,peiqi,black_girl;

names = []

names.append('old_driver')

......

names = ['old_driver','rain','jack','shanshan','peiqi','black_girl']

2、在names列表里面black_girl前面插入一个alax;

names.insert(5,'alax')

names = ['old_driver', 'rain', 'jack', 'shanshan', 'peiqi', 'alax', 'black_girl']

3、往names列表里rain后面插入一个子列表,[oldboy,oldgirl]

namse.insert(2,['oldboy','oldgirl'])

4、循环names列表,打印每个元素的索引值,和元素;

names=['old_driver','rain',['oldboy','oldgirl'],'jack','shanshan','peiqi','black_girl']
for i in names:
print(names.index(i),i)

Python初学者第六天 列表操作练习

5、循环names列表,打印每个元素的索引值,和元素。当索引值为偶数时,把对应的元素改为-1;

names=['old_driver','rain',['oldboy','oldgirl'],'jack','shanshan','peiqi','black_girl']
for i in names:
if names.index(i)%2 == 0:
names[names.index(i)] = -1
print(names)

Python初学者第六天 列表操作练习

6、names列表里面有3个2,请返回第2个2的索引值。不要人肉书,要动态找;

names=['old_driver',2,'rain',['oldboy','oldgirl'],2,'jack','shanshan','peiqi',2,'black_girl']

fisrt_index = names.index(2) #第一个2的索引
new_list = names[fisrt_index+1:] #将第一个2后面的列表切片
second_index = new_list.index(2) #在新的列表中找到第二个2的索引
second_val = names[fisrt_index+second_index+1] #第二个2在names列表中的索引等于第一个2索引和第二个2索引+1
print("second val:",second_val )

Python初学者第六天 列表操作练习

7、

Python初学者第六天 列表操作练习

products = [['Iphone8',6888],['MacPro',14800],['小米6',2499],['Coffee',31],['Booke',80],['Nike Shoes',799]]
print("--------商品列表---------")
for index,i in enumerate(products):
print("%s. %s %s" %(index,i[0],i[1]))



Python初学者第六天 列表操作练习


products = [['Iphone8',6888],['MacPro',14800],['小米6',2499],['Coffee',31],['Booke',80],['Nike Shoes',799]]
        break