php正则表达式无法在php中工作[preg_replace}

问题描述：

I am trying to remove the following html but my regex isn't working

<div class="vmargin"><div><iframe src="/test.php?u=N0Bhlant98C6MRj0D44HwJMuf5TdA%2F24oG9hQ2qqX6IR2IruUxVrrhLR4EpHQDvGtuHH4%2BLgJMBG6L5%2BTs6t6FfgCbo%3D&amp;b=5&amp;f=frame" style="width:718px;height:438px;border:0;margin:0;padding:0;" __idm_frm__="100"></iframe></div><div><a href="" class="report_video" data-video-id="732253" title="Report Video">Video Broken?</a></div></div>

I tried the following regex

preg_replace("@<div class=\"vmargin\".*?<\\/div>.*?<\\/div><\\/div>@s",'', $input);

What's wrong with it

我正在尝试删除以下html但我的正则表达式无效 p> ＆lt; div class =“vmargin”＆gt;＆lt; div＆gt;＆lt; iframe src =“/ test.php？u = N0Bhlant98C6MRj0D44HwJMuf5TdA％2F24oG9hQ2qqX6IR2IruUxVrrhLR4EpHQDvGtuHH4％2BLgJMBG6L5％2BTs6t6FfgCbo％3D＆amp; amp; b = 5＆amp; amp; amp; f = frame“style =”width：718px; height：438px; border：0; margin：0; padding：0;“ __idm_frm __ =“100”＆gt;＆lt; / iframe＆gt;＆lt; / div＆gt;＆lt; div＆gt;＆lt; a href =“”class =“report_video”data-video-id =“732253”title =“报告视频”＆gt; 视频已损坏？＆lt; / a＆gt;＆lt; / div＆gt;＆lt; / div＆gt; code> pre>

我尝试了以下正则表达式 p>


  preg_replace（“@＆lt; div class = \”vmargin \“。*？＆lt; \\ / div＆gt;。*？＆lt; \\ / div＆gt;＆lt; \\ / div＆gt; @s”，'  '，$ input）;  
  code>  pre> 
 
 它出了什么问题 p> 
  div>

答

Do not use \\ because in your closing divs, there are no \ character. Try this:

<div class=\"vmargin\".*?<\/div>.*?<\/div><\/div>

So:

$string = '<div class="vmargin"><div><iframe src="/test.php?u=N0Bhlant98C6MRj0D44HwJMuf5TdA%2F24oG9hQ2qqX6IR2IruUxVrrhLR4EpHQDvGtuHH4%2BLgJMBG6L5%2BTs6t6FfgCbo%3D&amp;b=5&amp;f=frame" style="width:718px;height:438px;border:0;margin:0;padding:0;" __idm_frm__="100"></iframe></div><div><a href="" class="report_video" data-video-id="732253" title="Report Video">Video Broken?</a></div></div>';
$input = preg_replace("@<div class=\"vmargin\".*?<\/div>.*?<\/div><\/div>@s", '', $string);
var_dump($input);

Output: string '' (length=0)

答

I know it's not technically an answer, but to make the result readable (code formatting required)

Works for me:

<?php

$input = '<div class="vmargin"><div><iframe src="/test.php?u=N0Bhlant98C6MRj0D44HwJMuf5TdA%2F24oG9hQ2qqX6IR2IruUxVrrhLR4EpHQDvGtuHH4%2BLgJMBG6L5%2BTs6t6FfgCbo%3D&amp;b=5&amp;f=frame" style="width:718px;height:438px;border:0;margin:0;padding:0;" __idm_frm__="100"></iframe></div><div><a href="" class="report_video" data-video-id="732253" title="Report Video">Video Broken?</a></div></div>';

echo( "!".preg_replace("@<div class=\"vmargin\".*?<\\/div>.*?<\\/div><\\/div>@s",'', $input) .'!' );

Output:

C:\test>php test.php
!!

Moving to ' quoted strings and removing the escaping makes it easier to read though

$input = '<div class="vmargin"><div><iframe src="/test.php?u=N0Bhlant98C6MRj0D44HwJMuf5TdA%2F24oG9hQ2qqX6IR2IruUxVrrhLR4EpHQDvGtuHH4%2BLgJMBG6L5%2BTs6t6FfgCbo%3D&amp;b=5&amp;f=frame" style="width:718px;height:438px;border:0;margin:0;padding:0;" __idm_frm__="100"></iframe></div><div><a href="" class="report_video" data-video-id="732253" title="Report Video">Video Broken?</a></div></div>';

echo( '!'.preg_replace('@<div class="vmargin".*?</div>.*?</div></div>@s','', $input) .'!' );

Same output

php正则表达式无法在php中工作[preg_replace}

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