java的List集合里面放了Map,List>,如何判定人名相同,就组合成一个对象?

public static void main(String[] args) {

        List<Map<String, Object>> list = new ArrayList<>();
        Map<String, Object> objectMap = new HashMap<>();
        objectMap.put("name","张三");
        objectMap.put("公司","腾讯");
        Map<String, Object> objectMap1 = new HashMap<>();
        objectMap1.put("name","李四");
        objectMap1.put("公司","阿里");
        Map<String, Object> objectMap2 = new HashMap<>();
        objectMap2.put("name","王五");
        objectMap2.put("公司","百度");
        Map<String, Object> objectMap3 = new HashMap<>();
        objectMap3.put("name","王五");
        objectMap3.put("地址","北京");
        list.add(objectMap);
        list.add(objectMap1);
        list.add(objectMap2);
        list.add(objectMap3);
        Map<String, Map<String,Object>> map = new HashMap<>();
        list.forEach((s)->{
            if(map.containsKey(s.get("name"))){
                Map<String, Object> map1 = map.get(s.get("name"));
                map1.putAll(s);
            }else{
                Map<String, Object> newMap = new HashMap<>();
                newMap.putAll(s);
                map.put(s.get("name").toString(),newMap);
            }
        });
        map.forEach((k,v)->{
            System.out.println(k);
            v.forEach((e,a)->{
                System.out.println(e+":"+a);
            });

        });
    }

参考博文：https://blog.csdn.net/weixin_41763995/article/details/80223244

思路，用 Map 的方式解决，遍历列表，以 name 为 key ，参考代码如下：

Map<String,Map<String,String>> nameAndElements = new HashMap<String,,Map<String,String>>();//以 name 为 key 存储合并后的数据
for(int i=0;i<data.size();i++){
  Map<String,String> temp = data.getIndexAt(i);
    String name = temp.get("name");
    if(nameAndElements.contains(name)){
      //存在，合并
        Map<String,String> currentInfo = nameAndElements.get(name);
        currentInfo.put("company",temp.get("company");
        currentInfo.put("address",temp.get("address");
    }else{
      // 新记录
        nameAndElements.put(name,temp);
    }
}