POJ 1008 Maya Calendar
很简单的历法转换问题，思路是全部统一成距离0:0:0的总日数，之后再按照格式计算即可。
有两个需要注意的：
1、输出的第一行需要是有3的，第一次WA就是因为忽视了这个问题
2、有一个Special Case:
4. uayet 259
正解是 13 ahau 364
而不是13 ahau 365
代码如下：
1 /* 2 * File: Maya.h 3 * Author: chrischeng021 <chrischeng021@gmail.com> 4 * 5 * Created on July 9, 2015, 4:14 PM 6 */ 7 8 #ifndef MAYA_H 9 #define MAYA_H 10 11 int input_num,flag = 0; 12 13 char *Tzolkin_Day_Name[] = {"imix", "ik", "akbal", "kan", "chicchan", "cimi", 14 "manik", "lamat", "muluk", "ok", "chuen", "eb", "ben", "ix", "mem", 15 "cib", "caban", "eznab", "canac", "ahau"}; 16 17 char *Haab_Month_Name[] = {"pop", "no", "zip", "zotz", "tzec", "xul", "yoxkin", 18 "mol", "chen", "yax", "zac", "ceh", "mac", "kankin", "muan", "pax", 19 "koyab", "cumhu", "uayet"}; 20 21 int calcularDays(char in_day[10],char in_month[5], int in_year){ 22 int days_from_begin = 0; 23 int day = atoi(in_day); 24 int cmpRet,i; 25 days_from_begin += 365 * in_year; 26 if(flag == 0){ 27 printf("%d ",input_num); 28 flag = -1; 29 } 30 for(i = 0; i< 19; i++){ 31 if((cmpRet = strcmp(Haab_Month_Name[i],in_month)) == 0){ 32 days_from_begin += 20 * i; 33 break; 34 } 35 else 36 continue; 37 } 38 days_from_begin += atoi(in_day) + 1; 39 return days_from_begin; 40 } 41 void calcularTzolkinDate(int days_from_begin){ 42 int ret_day; 43 int ret_ped; 44 int ret_yer; 45 int leftDays; 46 ret_yer = (days_from_begin%260 == 0 ? days_from_begin/260 - 1 : days_from_begin/260); 47 leftDays = days_from_begin - 260 * ret_yer; 48 ret_ped = (leftDays%13 == 0 ? 13 : leftDays%13); 49 ret_day = (leftDays%20 == 0 ? 20 : leftDays%20); 50 printf("%d %s %d ",ret_ped, Tzolkin_Day_Name[ret_day - 1],ret_yer); 51 } 52 53 void process(){ 54 int days_from_begin = 0,i; 55 char in_month[5]; 56 char in_day[10]; 57 int in_year; 58 scanf("%d",&input_num); 59 i = input_num; 60 while(i-- > 0){ 61 scanf("%s%s%d",in_day, in_month, &in_year); 62 days_from_begin = calcularDays(in_day, in_month, in_year); 63 calcularTzolkinDate(days_from_begin); 64 } 65 } 66 67 #endif /* MAYA_H */