关于链表的有关问题

关于链表的问题
表示实在是做不下去，基础不行啊。。。。尝试用链表做 结果改成四不像。。。。用没有那位大神耐心的改一下啊 准备之后好好复习了
#include <stdio.h> 
#include <string.h>
#include <stdlib.h>
#include <malloc.h>
#define SWN 4 /* ¿Î³ÌÊý */ 
#define NAMELEN 20 /* ÐÕÃû×î´ó×Ö·ûÊý */ 
#define CODELEN 10 /* ѧºÅ×î´ó×Ö·ûÊý */ 
#define FNAMELEN 80 /* ÎļþÃû×î´ó×Ö·ûÊý */ 
#define BUFLEN 80 /* »º³åÇø×î´ó×Ö·ûÊý */ 
/* ¿Î³ÌÃû³Æ±í */ 
char schoolwork[SWN][NAMELEN+1] = {"Chinese","Mathematic","English","physics"}; 
struct record 
{ 
int age;
char sex;
char name[NAMELEN+1];
char code[CODELEN+1]; 
int marks[SWN]; 
int total; 
}stu; 

struct node 
{ 
int age;
char sex;char name[NAMELEN+1];
char code[CODELEN+1]; 
int marks[SWN];//ÀûÓÃÕûÐÎÊý×é±£´æ¸÷¿ÆÄ¿³É¼¨ 
int total; 
struct node *next; /* ºóÐø±íÔªÖ¸Õë */ 
}*head; /* Á´±íÊ×Ö¸Õë */ 

int total[SWN]; 
FILE *stfpt; 
char stuf[FNAMELEN];
/* ´ÓÖ¸¶¨Îļþ¶ÁÈëÒ»¸ö¼Ç¼ */ 
int readrecord(FILE *fpt,struct record *rpt) 
{ 
char buf[BUFLEN]; 
int i; 
if(fscanf(fpt,"%s",buf)!=1) 
return 0; /* Îļþ½áÊø */ 
strncpy(rpt->name,buf,NAMELEN); 
fscanf(fpt,"%s",buf); 
strncpy(rpt->code,buf,CODELEN); 
for(i=0;i<SWN;i++) 
fscanf(fpt,"%d",&rpt->marks[i]); 
for(rpt->total=0,i=0;i<SWN;i++) 
rpt->total+=rpt->marks[i]; 
return 1; 
} 


/* ¶ÔÖ¸¶¨ÎļþдÈëÒ»¸ö¼Ç¼ */ 
int writerecord(FILE *fpt,struct record *rpt) 
{ 
int i; 
fprintf(fpt,"%s\n",rpt->name); 
fprintf(fpt,"%s\n",rpt->code); 
for(i=0;i<SWN;i++) 
fprintf(fpt,"%d\n",rpt->marks[i]); 
return 0; 
} 

/* ÏÔʾѧÉú¼Ç¼ */ 
void display(struct record *rpt) 
{ 
int i; 
printf("\nName : %s\n",rpt->name); 
printf("Code : %s\n",rpt->code); 
printf("Marks :\n"); 
for(i=0;i<SWN;i++) 
printf(" %-15s : %4d\n",schoolwork[i],rpt->marks[i]); 
printf("Total : %4d\n",rpt->total); 
} 

/* ¼ÆËã¸÷µ¥¿Æ×Ü·Ö */ 
int totalmark(char *fname) 
{ 
FILE *fp; 
struct record s; 
int count,i; 
if((fp=fopen(fname,"r"))==NULL) 
{ 
printf("Can't open file %s.\n",fname); 
return 0; 
} 
for(i=0;i<SWN;i++) //ÖÃÁã
total[i]=0; 
count=0;