兄弟们 帮帮忙哈~c语言指针函数的有关问题

兄弟们 帮帮忙哈~c语言指针函数的问题！
题目：不断的输入数字字符，统计个数字键被按得次数

书上的答案如下：

        #include   "stdio.h "
        #include   "stdlib.h "
        #include   "conio.h "
        #include   "ctype.h "

        int   *cace()
        {
        int   *pcounters;
        int   ch;
        pcounters=(int*)   malloc   (10*sizeof(int));
        for   (ch= '0 ';ch <= '9 ';ch++)
        *   (pcouneters+(ch- '0 '))=0;
        printf   ( "input   digital,please.   @   for   to   END\n ");
        while   (ch=getche   ())
        {
        if(ch== '@ ')   break;
        if(!   isdigit   (ch))   coutinue;
        pcounters   [ch- '0 ']   ++;
        }
        printf( ".\n ");
        return   pcounters;
        }
        main()
        {
        int   *pcount,k;
        pcount   =cace();
        for   (k=0;k <10;k++)
        printf( "%c   digital   key   pressed   %d   times.   \n ",k+ '0 ',pcount[k]);
        free   (pcount);
       
}

我按照上面   一字不漏的输入，却出现以下3个错误：

1             *   (pcouneters+(ch- '0 '))=0;

2         while   (ch=getche   ())

3         if(!   isdigit   (ch))   coutinue;

请问各位大虾这个是什莫问题呢？谢谢

------解决方案--------------------
//盖好了，有几个单词拼写错误，呵呵，其他没问题
#include "stdafx.h "
#include "stdio.h "
#include "stdlib.h "
#include "conio.h "
#include "ctype.h "

int *cace()
{
int *pcounters;
int ch;
pcounters=(int*) malloc (10*sizeof(int));//special
for (ch= '0 ';ch <= '9 ';ch++)
*(pcounters+(ch- '0 '))=0; //special
printf ( "input digital,please. @ for to END\n ");
while (ch=getche ())
{
if(ch== '@ ') break;
if(! isdigit (ch)) continue;//special
pcounters [ch- '0 '] ++;
}
printf( ".\n ");
return pcounters;
}
main()
{
int *pcount,k;
pcount =cace();
for (k=0;k <10;k++)
printf( "%c digital key pressed %d times. \n ",k+ '0 ',pcount[k]);
free (pcount);

}