求教指针函数的有关问题
求教指针函数的问题
void Function(int* a, int* n){
if (a) delete[] (a);
a = new int[10];
memset(a, 0, 10*sizeof(int));
*n = 10;
}
void main(){
int* a = NULL;
int n = 0;
Function(a, &n);
for (int i=0; i<n; i++){
cout << "a[" << i << "]=" << a[i] << "\n";
}
if (a) delete[] a;
结果是要输出i个0,上面的输不出,除了下面的修改方法之外,还有其他什么不算太复杂的改法吗...老师叫再想两种,求赐教!
void Function(int** a, int* n){
if (*a) delete[] (*a);
(*a) = new int[10];
memset((*a), 0, 10*sizeof(int));
*n = 10;
}
void main(){
int* a = NULL;
int n = 0;
Function(&a, &n);
for (int i=0; i<n; i++){
cout << "a[" << i << "]=" << a[i] << "\n";
}
if (a) delete[] a;
}
------解决方案--------------------
void Function(int* a, int* n){
if (a) delete[] (a);
a = new int[10];
memset(a, 0, 10*sizeof(int));
*n = 10;
}
void main(){
int* a = NULL;
int n = 0;
Function(a, &n);
for (int i=0; i<n; i++){
cout << "a[" << i << "]=" << a[i] << "\n";
}
if (a) delete[] a;
结果是要输出i个0,上面的输不出,除了下面的修改方法之外,还有其他什么不算太复杂的改法吗...老师叫再想两种,求赐教!
void Function(int** a, int* n){
if (*a) delete[] (*a);
(*a) = new int[10];
memset((*a), 0, 10*sizeof(int));
*n = 10;
}
void main(){
int* a = NULL;
int n = 0;
Function(&a, &n);
for (int i=0; i<n; i++){
cout << "a[" << i << "]=" << a[i] << "\n";
}
if (a) delete[] a;
}
------解决方案--------------------
- C/C++ code
#include <iostream> using namespace std; int *Function(int* a, int* n){ if (a) delete[] (a); a = new int[10]; memset(a, 0, 10*sizeof(int)); *n = 10; return a; } void main() { int* a = NULL; int n = 0; a=Function(a, &n); for (int i=0; i<n; i++){ cout << "a[" << i << "]=" << a[i] << "\n"; } if (a) delete[] a; }