在php脚本中返回shell_exec（）函数的参数

问题描述：

I am calling executable file with main() function from php script using exec(). Which works fine but return all printf() values rather only returning array:

main.cpp:

#include<stdio.h>
#include<string.h>
#include "foo.h"
int main(int argc, char *argv[] )
{
    char buffer[1024];
    char *ch;
    static int ar[2];
    strcpy(buffer,argv[1]);
    printf("Client : 
");
    if ( argc != 2 ) /* argc should be 2 for correct execution */
    {
              printf( "
%s filename
", argv[0] );
    }
    else 
    {
        printf("
string is :%s 
",buffer);
    ch=foo(buffer);
    ar[0]=((int*)ch)[0];
    ar[1]=((int*)ch)[1];
    printf("Counts is :%d  %d 
",ar[0],ar[1]);
    }
    return (int)ar;

}

my test.php

<?php
$s="critic worst";
escapeshellarg($s);
$a=array(shell_exec('/home/technoworld/Videos/LinSocket/client "nice bad"'));
print_r($a[0]);
//echo exec('whoami');
?>

Which shows output:

Client : string is :nice bad Positive count: 2 Negative count: 2 array item2 2 Count is :2 2

I also tried with exec() which also gives same prob. Can any one suggest how to get ar[0] and ar[1] from main.cpp?

Client : string is :nice bad Positive count: 2 Negative count: 2 array item2 2

This is from all printf() present in foo.cpp file.

When I use exec() then it gives Count is :2 2

How to get exact ar[0] and ar[1]

我使用exec（）从php脚本调用带main（）函数的可执行文件。哪个工作正常，但返回所有printf（）值，而只返回数组： p>

main.cpp： p>

  #include＆lt; stdio.h＆gt  ; 
 #include＆lt; string.h＆gt; 
 #include“foo.h”
int main（int argc，char * argv []）
 {
 char buffer [1024]; 
 char * ch; \  n static int ar [2]; 
 strcpy（buffer，argv [1]）; 
 printf（“Client：
”）; 
 if（argc！= 2）/ * argc应为2以便正确执行 * / 
 {
 printf（“
％s filename 
”，argv [0]）; 
} 
 else 
 {
 printf（“
string is：％s 
”，buffer  ）; 
 ch = foo（缓冲区）; 
 ar [0] =（（int *）ch）[0]; 
 ar [1] =（（int *）ch）[1]; 
 printf  （“计数是：％d％d 
”，ar [0]，ar [1]）; 
} 
 return（int）ar; 
 
} 
  code>  pre>  
 
  my test.php  p> 
 
 
 ＆lt;？php 
 $ s =“crit worst”; 
escapeshellarg（$ s）; 
 $ a  = array（shell_exec（'/ home / technoworld / Videos / LinSocket / client“nice bad”'））; 
print_r（$ a [0]）; 
 // echo exec（'whoami'）; 
？＆gt;  ; 
  code>  pre> 
 
 显示输出： p> 
 
 
 客户端：字符串是： 好坏正计数：2负数：2数组项2 2计数是：2 2 
  code>  pre> 
 
  我也试过exec（）也给出了同样的问题 。 任何人都可以建议如何从main.cpp获取ar [0]和ar [1]吗？ strong>  p> 
 
 
 客户端：字符串是：好坏正数：2 负数：2数组项2 2 
  code>  pre> 
 
 这是来自foo.cpp文件中的所有printf（）。 p> 
 
 
 我使用exec（）然后它给出 Count is：2 2  code>  p> 
 
 
如何获得精确的ar [0]和ar [1]  p> 
   DIV>

答

Perhaps simply

preg_match('/[0-9]*/', $output, $matches);

If I'm not mistaken...

To be sure:

preg_match('Counts is :([0-9]*)[^0-9]*([0-9]*)/',$output,$matches);

Also have a look at this question to find ouy how to use PHP and C(++) interactively

A quick, and hacky ugly messy workaround could be:

printf("%d",ar[0]);
return ar[1];//end main function

Then, in your PHP script:

$a = array(shell_exec('/home/technoworld/Videos/LinSocket/client "nice bad"'),
           shel_exec('echo $?');
);

Then get the last numeric value from the output string, (preg_match('/([0-9]*)\w*$/',$a[0],$matches); should do it, and $a[1] will contain the value of ar[1] of the main.cpp file, because that was the exit code. Note that exit codes aren't for show. The signify something! Changeing them is generally a bad idea. I'd just change my main.cpp, and add the line:

printf("@ar[0]=%d;ar[1]=%d@",ar[0],ar[1]);

This prints a clearly formatted string, which is easy to parse using a regular expression. Assuming *ar held values 123 and 456 respectively:

preg_match_all('/\]\=([^;@]*)/',$a[0],$matches);
var_dump($matches[1]);//[123,456]

Or better stil:

$parts = explode('@', $a[0]);
echo $parts[1];//ar[0]=123;ar[1]=456

Bottom line:

Add this to your main function in main.cpp:

printf("@ar[0]=%d;ar[1]=%d@",ar[0],ar[1]);

and, to get the int values in php:

$a = array(shell_exec('..'));
preg_match_all('/[^=]*\=([^;@]*)/',$a[0],$matches);
var_dump($matches[1]);

That should do it.

$a = array();
$b = array();
if (preg_match_all('/[^=]*\=([^;@]*)/', shell_exec('your command'), $matches))
{
   $a[] = (int) $matches[1][0];//optionally cast to int
   $b[] = (int) $matches[1][1];
}

That's all... not sure why $a and $b need to be arrays, but that's probably because you're going to call the client bin a couple of times.

答

Thanks to Elias for help. This is the solution:

<?php

if (preg_match_all('/[^=]*\=([^;@]*)/', shell_exec('/home/technoworld/Videos/LinSocket/client "nice bad worst good"'), $matches))
{
   $x = (int) $matches[1][0];//optionally cast to int
   $y = (int) $matches[1][1];
   echo $x. '<br/>'. $y. '<br/>'
}

?>

$x,$y contain ar[0] and ar[1] respectively

答

This will also work:

if (preg_match_all('/[^=]*=([^;@]*)/', shell_exec("/home/technoworld/Videos/LinSocket/client '$s'"), $matches)) //Values stored in ma.
{
    $x = (int) $matches[1][0];  //optionally cast to int
    $y = (int) $matches[1][1];
}

echo "<br/>"; echo "Positive count :$x";
echo "<br/>"; echo "Negative count :$y"; echo "<br/>";

在php脚本中返回shell_exec（）函数的参数

相关推荐