Spring配置文件在tomcat启动时报错解决方案

Spring配置文件在tomcat启动时报错
大家好，我tomcat在启动时，报这个错：

org.springframework.beans.factory.BeanDefinitionStoreException: IOException parsing XML document from ServletContext resource [/WEB-INF/applicationContext.xml]; nested exception is java.io.FileNotFoundException: Could not open ServletContext resource [/WEB-INF/applicationContext.xml]

web.xml中是这样写的：

<?xml version="1.0" encoding="UTF-8"?>

<web-app version="2.5" 

	xmlns="http://java.sun.com/xml/ns/javaee" 

	xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 

	xsi:schemaLocation="http://java.sun.com/xml/ns/javaee 

	http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">

  <welcome-file-list>

    <welcome-file>index.jsp</welcome-file>

  </welcome-file-list>

  

  	<listener>

		<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>

		<!-- default: /WEB-INF/applicationContext.xml -->

	</listener>


	<context-param>

		<param-name>contextConfigLocation</param-name>

		<!-- <param-value>/WEB-INF/applicationContext-*.xml,classpath*:applicationContext-*.xml</param-value>  -->

		<param-value>classpath:beans.xml</param-value>

	</context-param>


		<filter>

		<filter-name>struts2</filter-name>

		<filter-class>org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter</filter-class>

	</filter>


	<filter-mapping>

		<filter-name>struts2</filter-name>

		<url-pattern>/*</url-pattern>

	</filter-mapping>

  

</web-app>

spring的beans.xml位于src目录下，里面内容是这样的：

<?xml version="1.0" encoding="UTF-8"?>

<beans xmlns="http://www.springframework.org/schema/beans"

	xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"

	xmlns:context="http://www.springframework.org/schema/context"

	xmlns:aop="http://www.springframework.org/schema/aop"

	xmlns:tx="http://www.springframework.org/schema/tx"

	xsi:schemaLocation="http://www.springframework.org/schema/beans

           http://www.springframework.org/schema/beans/spring-beans-2.5.xsd

           http://www.springframework.org/schema/context

           http://www.springframework.org/schema/context/spring-context-2.5.xsd

           http://www.springframework.org/schema/aop

           http://www.springframework.org/schema/aop/spring-aop-2.5.xsd

           http://www.springframework.org/schema/tx 

           http://www.springframework.org/schema/tx/spring-tx-2.5.xsd">

	<context:annotation-config />

	<context:component-scan base-package="com.uds" />



	<bean

		class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">

		<property name="locations">

			<value>classpath:jdbc.properties</value>

		</property>

	</bean>


	<bean id="dataSource" destroy-method="close"

		class="org.apache.commons.dbcp.BasicDataSource">

Spring配置文件在tomcat启动时报错解决方案

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