Datagridview将值传递到文本框

问题描述：

我使用c#.net Windows应用程序，我需要在双击datagrid rowcell时将值传递给另一种形式的文本框，并且需要编辑并再次保存到另一种形式的同一个网格中

Hi iam using c#.net windows application i need to pass values to textboxes in another form on double click of datagrid rowcell and need to edit and again save to the same grid which is another form

答

纳伦德拉，

请执行以下步骤，可能会对您有所帮助.

1.以您要打开的形式声明一个构造函数和一个公共变量.

Hi Narendra,

Follow this steps it may help you.

1. declare a constructor and a public variable in the form which you want to open.

public  string strvalue = string.Empty;
        public Form2()
        {
            InitializeComponent();
        }
        public Form2(string str)
        {
            strvalue = str;
            InitializeComponent();
        }

2.像这样打开form2

2.Open form2 like this

private void dataGridView1_CellContentClick(object sender, DataGridViewCellEventArgs e)
        {
            if (e.RowIndex != -1)
            {
                if (e.ColumnIndex != 1)
                {
                    if (!string.IsNullOrEmpty(dataGridView1.Rows[e.RowIndex].Cells[e.ColumnIndex].Value.ToString()))
                    {
                        string strValue = dataGridView1.Rows[e.RowIndex].Cells[e.ColumnIndex].Value.ToString();
                        Form2 _Form2 = new Form2(strValue);
                        _Form2.ShowDialog();
                        dataGridView1.Rows[e.RowIndex].Cells[e.ColumnIndex].Value = _Form2.strvalue;
                        dataGridView1.Refresh();
                    }
                }
            }
        }

3.在事件上关闭form2并在变量中设置值.

3. Close form2 on a event and set value in variable.

private void button1_Click(object sender, EventArgs e)
       {
           strvalue = textBox1.Text;
           this.Close();
       }

希望这对您有帮助，

Hope this will help you,

private void GetValueFromDGVToTextBox()
        {
            int row = this.dataGridView1.CurrentCell.RowIndex;
            if (row > -1)
            {
                string value = this.dataGridView1[1, row].FormattedValue.ToString();
                textBox1.Text = value;
            }
        }

Datagridview将值传递到文本框

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