从字符串列表的元素中删除尾随换行符
问题描述:
我必须在表格中列出一大串单词:
I have to take a large list of words in the form:
['this
', 'is
', 'a
', 'list
', 'of
', 'words
']
然后使用strip函数,把它变成:
and then using the strip function, turn it into:
['this', 'is', 'a', 'list', 'of', 'words']
我认为我写的东西会起作用,但我不断收到错误消息:
I thought that what I had written would work, but I keep getting an error saying:
"'list' 对象没有属性 'strip'"
"'list' object has no attribute 'strip'"
这是我试过的代码:
strip_list = []
for lengths in range(1,20):
strip_list.append(0) #longest word in the text file is 20 characters long
for a in lines:
strip_list.append(lines[a].strip())
答
您可以使用列表推导式
my_list = ['this
', 'is
', 'a
', 'list
', 'of
', 'words
']
stripped = [s.strip() for s in my_list]
或者使用 map()
:
stripped = list(map(str.strip, my_list))
在 Python 2 中,map()
直接返回一个列表,因此您不需要调用列表.在 Python 3 中,列表推导式更简洁,通常被认为更惯用.
In Python 2, map()
directly returned a list, so you didn't need the call to list. In Python 3, the list comprehension is more concise and generally considered more idiomatic.