【php】php输出jquery的轮询，5秒跳转指定url
1、在php中直接输出jquery的轮询，5秒后跳转指定url
2、代码稍微改动，即可在html中使用
3、代码：
public function alpha(){ $html = '<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <script src="http://weixin.jimuc.com/app/resource/js/lib/jquery-1.11.1.min.js"></script> <title>积慕商城午夜订购</title> </head> <body>'; $html.= "<img src='http://pms.jimuc.com/index.php?m=file&f=read&t=png&fileID=130' style=' 100%;height: 100%;'/> <input class='loginTime' value='5' type='hidden'>"; $html.= "<script type='text/javascript'> var loginTime = parseInt($('.loginTime').val()); var time = setInterval(function(){ console.log(loginTime); loginTime = loginTime-1; $('.loginTime').val(loginTime); if(loginTime == 0){ window.location.href = '$url'; } },1000); </script>"; $html.= '</body> </html>'; print_r($html);exit; }
4、效果：