获取 xml 元素在 SQL Server 2012 中的位置

问题描述：

如何使用 SQL Server 2012 获取行的行号?

How to get the row number for the rows using SQL Server 2012?

这里是xml

<Rows>
   <Row>Coating</Row>
   <Row>Drying</Row>
   <Row>Waxing</Row>
</Rows>

我需要这样返回的数据

RowLabel  RowNumber
-------------------
Coating    1
Drying     2
Waxing     3

答

您可以使用一些关于 SQL Server 如何实现 XML 分解的内部知识，并像这样使用 row_number().

You can use some internal knowledge about how SQL Server implements XML shredding and use row_number() like this.

declare @XML xml = 
'<Rows>
   <Row>Coating</Row>
   <Row>Drying</Row>
   <Row>Waxing</Row>
</Rows>'

select T.X.value('text()[1]', 'nvarchar(100)') as RowLabel,
       row_number() over(order by T.X) as RowNumber
from @XML.nodes('/Rows/Row') as T(X)

Ref: 唯一识别 XML具有 DENSE_RANK 的节点

或者您可以谨慎行事"并使用数字表.

Or you can "play it safe" and use a numbers table.

select T.X.value('text()[1]', 'nvarchar(100)') as RowLabel,
       N.Number as RowNumber
from Numbers as N
  cross apply @XML.nodes('/Rows/Row[sql:column("N.Number")]') as T(X)
where N.Number between 1 and @XML.value('count(/Rows/Row)', 'int')

获取 xml 元素在 SQL Server 2012 中的位置

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