sed使用包含反斜杠的字符串进行替换
我需要使用包含反斜杠（REVERSE SOLIDUS）字符的Windows样式目录路径替换文件中的文本。我已经在使用替代表达式分隔符。反斜杠似乎被视为转义字符。
I need to replace text in a file with a Windows-style directory path containing backslash (REVERSE SOLIDUS) characters. I am already using an alternative expression delimiter. The backslashes appear to be treated as escape characters.
如何在输出中保留反斜杠？
How can I keep the backslashes in the output?
$ echo DIR=foobar | sed -e "s#DIR=.*#$(cygpath -w $(pwd))#"
C:gwin64homelit
所需的输出是：
C:\cygwin64\home\lit
您必须转义 sed 替换模式。幸运的是，其中只有三个：& ， \ 和定界符 / （请参阅此问题和此）。在您的情况下，由于您使用＃作为分隔符，因此必须转义＃而不是 / 。
You'll have to escape metacharacters in sed replacement pattern. Fortunately, there are only three of those: &, \, and a delimiter / (see this question and this). In your case, since you're using # for delimiter, you'll have to escape # instead of /.
您可以创建一个帮助程序shell函数（例如此处）：
You can create a helper shell function (like here):
escapeSubst() { sed 's/[&#\]/\\&/g'; }
，然后将字符串传递给 sed ，像这样：
and then pass your string through it before giving it to sed, like this:
$ echo DIR=foobar | sed -e "s#DIR=.*#$(cygpath -w $(pwd) | escapeSubst)#"
C:\cygwin64\home\lit