使用BeautifulSoup获取标签名称
问题描述：
from bs4 import BeautifulSoup
source_code = """<a href="#" name="linkName">ok</a>"""
soup = BeautifulSoup(source_code)
print soup.a.? #find the object name
使用上面显示的代码，我试图打印锚标记'name'，它是linkName，但是我不确定我将使用哪个模块或对象，我已经尝试过contents，name和tag_name_re.
Using the code displayed above, i am trying to print the anchor tags 'name' which is linkName but i'm not sure which module or object i will be using, i have tried contents,name and tag_name_re.
有人可以帮我吗?谢谢！
Can anybody help me out? thanks!
答
您已经回答了问题.
soup.a['name']
修改
如果您有多个a元素，则可以执行以下操作:
If you have more than one a element, you can do this:
x = """<x><a name="foo"/><a name="bar"/></x>"""
s = bs4.BeautifulSoup(x)
for a in s.findChildren("a"):
print(a["name"])