projecteuler Problem 9 Special Pythagorean triplet

projecteuler   Problem 9  Special Pythagorean triplet

A Pythagorean triplet is a set of three natural numbers, a < b < c, for which,

a2 + b2 = c2

For example, 32 + 42 = 9 + 16 = 25 = 52.

There exists exactly one Pythagorean triplet for which a + b + c = 1000.
Find the product abc.

译文:一个毕达哥拉斯三元数组是由三个自然数组成,a<b<c,形如

projecteuler   Problem 9  Special Pythagorean triplet

举个例子,32 + 42 = 9 + 16 = 25 = 52.

现在存在一个毕达哥拉斯三元数组,它满足 a + b + c = 1000.毕达哥拉斯三元数组的数值乘积。


第一次code:

 1 public class Main
 2 { 
 3     public static void main(String[] args) 
 4     { 
 5         System.out.println(run(1000));
 6     }
 7     public static String run(int n)
 8     {
 9         String a="";
10         for(int i=1;i<n;i++)
11         {
12             for(int j=0;j<i;j++)
13             {
14                 for(int s=0;s<j;s++)
15                 {
16                     if(s*s+j*j==i*i)
17                     {
18                          if(s+j+i == 1000)
19                          {
20                              a =String.valueOf(s*j*i);
21                          }
22                     }
23                 }
24             }
25         }
26         return a;
27     }
28 }

时间效率:280毫秒。