Python脚本递归重命名文件夹和子文件夹中的所有文件

问题描述：

我有许多不同的文件需要重命名为其他文件.我已经做到了这一点，但我想拥有它，以便我可以有许多项目要替换及其相应的替换项，而不是键入每个项目，然后运行代码然后再次重新键入.

Hi I have a number of different files that need to be renamed to something else. I got this far but I want to have it so that I can have many items to replace and their corresponding replacements rather than type each one out, run the code then retype it again.

更新*此外，我需要重命名以仅更改文件的一部分而不是整个文件，因此如果有Cat5e_1mBend1bottom50m2mBend2top-Aqeoiu31"，它只会将其更改为'Cat5e50m1mBED_50m2mBE2U-Aqeoiu31"

UPDATE* Also I need the rename to only change part of the file not the whole thing so if there was a "Cat5e_1mBend1bottom50m2mBend2top-Aqeoiu31" it would just change it to "'Cat5e50m1mBED_50m2mBE2U-Aqeoiu31"

import os, glob

#searches for roots, directory and files
for root,dirs, files in os.walk(r"H:\My Documents\CrossTalk\\"):
   for f in files:
       if f == "Cat5e_1mBend1bottom50m2mBend2top":#string you want to rename
          try:
             os.rename('Cat5e_1mBend1bottom50m2mBend2top', 'Cat5e50m1mBED_50m2mBE2U'))
          except FileNotFoundError, e:
             print(str(e))

答

这是你想要的吗?

import os, glob
#searches for roots, directory and files
#Path
p=r"C:\\Users\\joao.limberger\\Documents\\Nova Pasta"
# rename arquivo1.txt to arquivo33.txt and arquivo2.txt to arquivo44.txt
renames={"arquivo1.txt":"arquivo33.txt","arquivo2.txt":"arquivo44.txt"}
for root,dirs,files in os.walk(p):
   for f in files:
      if f in renames.keys():#string you want to rename
         try:
            os.rename(os.path.join(root , f), os.path.join(root , renames[f]))
            print("Renaming ",f,"to",renames[f])
         except FileNotFoundError as e:
            print(str(e))

检查这是否是您想要的！！！

Check if this is wath you want!!!

import os, glob
#searches for roots, directory and files
#Python 2.7
#Path 
p=r"C:\\Users\\joao.limberger\\Documents\\Nova Pasta"
#  if the substring in the key exist in filename, replace the substring 
#   from the value of the key
#   if the key is "o1" and the value is "oPrinc1" and the filename is
#  arquivo1.txt ... The filename whil be renamed to "arquivoPrinc1.txt"
renames={"o1":"oPrinc1","oldSubs":"newSubs"}
for root,dirs,files in os.walk(p):
    for f in files:
        for r in renames:
            if r in f:
                newFile = f.replace(r,renames[r],1)
                try:
                    os.rename(os.path.join(root , f), os.path.join(root , newFile))
                    print "Renaming ",f,"to",newFile
                except FileNotFoundError , e:
                    print str(e)

Python脚本递归重命名文件夹和子文件夹中的所有文件

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