防止刷新浏览器时重新提交提交
下面的代码非常有用.在名为Submit.php的文件上,用户可以通过表单输入提交内容.表单转到Submit2.php,其中一些代码将提交的内容插入到MySQL数据库中.到目前为止一切顺利.
The code below all works great. On a file called submit.php, a user can enter a submission through a form. The form goes to submit2.php, where some code inserts the submission into a MySQL database. So far so good.
这是问题所在:用户登录到Submit2.php后,如果用户刷新浏览器,则会出现确认表单重新提交"弹出框.然后,如果用户在该弹出窗口中单击继续",则提交将重新提交到MySQL数据库.
Here's the problem: once the user has landed on submit2.php, if the user refreshes the browser, a "Confirm Form Resubmission" pop-up box appears. Then, if the user hits "Continue" on that pop-up, the submission will be re-submitted to the MySQL database.
如何使其在submit2.php上执行以下操作:
How can make it do the following on submit2.php:
-
如果刷新浏览器,则不会出现弹出窗口.
The pop-up will not appear if the browser is refreshed.
提交内容不会重新提交到数据库.
The submission will not be re-submitted to the database.
预先感谢
约翰
在submit.php上:
On submit.php:
echo '<form action="http://www.domain.com/sample/submit2.php" method="post">
<input type="hidden" value="'.$_SESSION['loginid'].'" name="uid">
<div class="submissiontitle"><label for="title">Story Title:</label></div>
<div class="submissionfield"><input name="title" type="title" id="title" maxlength="1000"></div>
<div class="urltitle"><label for="url">Link:</label></div>
<div class="urlfield"><input name="url" type="text" id="url" maxlength="500"></div>
<div class="submissionbutton"><input name="submit" type="submit" value="Submit"></div>
</form>
';
在submit2.php上:
On submit2.php:
if (isLoggedIn() == true)
{
$remove_array = array('http://www.', 'http://', 'https://', 'https://www.', 'www.');
$cleanurl = str_replace($remove_array, "", $_POST['url']);
$cleanurl = strtolower($cleanurl);
$cleanurl = preg_replace('/\/$/','',$cleanurl);
$cleanurl = stripslashes($cleanurl);
$title = $_POST['title'];
$uid = $_POST['uid'];
$title = mysql_real_escape_string($title);
$title = stripslashes($title);
$slug = str_replace(' ', '-', $title);
echo '-'.$site1.'-';
$cleanurl = mysql_real_escape_string(trim($cleanurl));
$site1 = 'http://' . $cleanurl;
$displayurl = parse_url($site1, PHP_URL_HOST);
function isURL($url1 = NULL) {
if($url1==NULL) return false;
$protocol = '(http://|https://)';
$allowed = '[-a-z0-9]{1,63}';
$regex = "^". $protocol . // must include the protocol
'(' . $allowed . '\.)'. // 1 or several sub domains with a max of 63 chars
'[a-z]' . '{2,6}'; // followed by a TLD
if(eregi($regex, $url1)==true) return true;
else return false;
}
if(isURL($site1)==true)
mysql_query("INSERT INTO submission VALUES (NULL, '$uid', '$title', '$slug', '$cleanurl', '$displayurl', NULL)");
else
echo "<p class=\"topicu\">Not a valid URL.</p>\n";
} else {
// user is not loggedin
show_loginform();
}