奇怪的重复模板模式（CRTP）与静态constexpr在Clang
问题描述：
请看下面的简单示例：
#include <iostream>
template <typename T>
class Base
{
public:
static constexpr int y = T::x;
};
class Derived : public Base<Derived>
{
public:
static constexpr int x = 5;
};
int main()
{
std::cout << Derived::y << std::endl;
}
在g ++中，这会编译精细并打印 5 。然而，在Clang中，它无法编译错误没有成员名为'x'在'Derived'。据我所知，这是正确的代码。
In g++, this compiles fine and prints 5 as expected. In Clang, however, it fails to compile with the error no member named 'x' in 'Derived'. As far as I can tell this is correct code. Is there something wrong with what I am doing, and if not, is there a way to have this work in Clang?
答
是否有办法在Clang中进行这项工作？这可能不是任何人都会寻找的答案，但我通过添加第三个类解决了这个问题：
This probably isn't the answer anyone would be looking for, but I solved the problem by adding a third class:
#include <iostream>
template <typename T>
class Base
{
public:
static constexpr int y = T::x;
};
class Data
{
public:
static constexpr int x = 5;
};
class Derived : public Base<Data>, public Data {};
int main()
{
std::cout << Derived::y << std::endl;
}
它可以按照需要工作，但不幸的是，它并没有真正的好处CRTP！
It works as desired, but unfortunately it doesn't really have the benefits of CRTP!