如何使用SimpleXML获取具有名称空间的节点的属性?
问题描述：
youtube.xml
<feed xmlns="http://www.w3.org/2005/Atom" xmlns:media="http://search.yahoo.com/mrss/" xmlns:openSearch="http://a9.com/-/spec/opensearchrss/1.0/" xmlns:gd="http://schemas.google.com/g/2005" xmlns:yt="http://gdata.youtube.com/schemas/2007">
<entry>
...
<yt:duration seconds="1870"/>
...
</entry>
</feed>
update_videos.php
$source = 'youtube.xml';
// load as file
$youtube = new SimpleXMLElement($source, null, true);
foreach($youtube->entry as $item){
//title works
echo $item->title;
//now how to get seconds? My attempt...
$namespaces = $item->getNameSpaces(true);
$yt = $item->children($namespaces['yt']);
$seconds = $yt->duration->attributes();
echo $seconds['seconds'];
//but doesn't work :(
}
答
所以我找到了一种使用xpath的方法，这是最好的方法还是与我的问题代码保持一致的方法?只是出于好奇.
So I found a way to do it using xpath, is this the best way or is there a way that's consistent with my code in the question? Just out of curiosity.
$source = 'youtube.xml';
// load as file
$youtube = new SimpleXMLElement($source, null, true);
$youtube->registerXPathNamespace('yt', 'http://gdata.youtube.com/schemas/2007');
$count = 0;
foreach($youtube->entry as $item){
//title works
echo $item->title;
$attributes = $item->xpath('//yt:duration/@seconds');
echo $attributes[$count]['seconds'];
$count++;
}