Ionic 2 - 如何在Android上使用后退按钮退出应用程序？

问题描述：

我搜索了当按下后退按钮时如何让Ionic2应用程序退出，但是我发现完全相反的问题，例如当按下后退按钮时如何防止退出Ionic2应用程序？。这就是我想要的，但是当我按下时它会在最近的标签之间切换。

I googled how to make Ionic2 app exit when back button is pressed, however I find totally opposite questions like "How to prevent exiting Ionic2 app when back button pressed?". This is what I want but it keeps switching between the recent tabs when I press back.

我刚用离子启动--v2 myProject标签开始了这个项目，并没有改变任何东西。

I just started the project with ionic start --v2 myProject tabs and didn't change anything.

如果在Android设备上按下后退按钮，我怎么强制它退出？

How can I force it to exit whenever back button is pressed on Android devices?

答

要按退回按钮退出应用程序，您必须在构造函数中注册硬件后退按钮，如下所示。

To exit the app on back button press, you have to register your hardware back button inside your constructor as follows.

constructor(){
    this.platform.ready().then(() => {
            this.platform.registerBackButtonAction(() => {
                navigator['app'].exitApp();                
            });
        });
}

但这适用于所有页面。要了解有关处理硬件后退按钮的更多信息，请 http://ionicframework.com/docs/v2 / api / platform / Platform /

But this will be applicable to all the pages. To know more about handling hardware back button check http://ionicframework.com/docs/v2/api/platform/Platform/

Ionic 2 - 如何在Android上使用后退按钮退出应用程序？

相关推荐