如何从int转换为String？

问题描述：

我正在开发一个项目，其中从 int 到 String 的所有转换都是这样完成的：

I'm working on a project where all conversions from int to String are done like this:

int i = 5;
String strI = "" + i;

我不熟悉Java。这是通常的做法还是有问题，正如我想的那样？

I'm not familiar with Java. Is this usual practice or is something wrong, as I suppose?

答

正常方式是整数。 toString（i）或 String.valueOf（i）。

串联将工作，但它是非常规的，可能是一个难闻的气味，因为它表明作者不知道上面的两种方法（还有什么他们可能不知道？）。

The concatenation will work, but it is unconventional and could be a bad smell as it suggests the author doesn't know about the two methods above (what else might they not know?).

当与字符串一起使用时，Java对+运算符有特殊支持（参见文档）翻译您发布的代码：

Java has special support for the + operator when used with strings (see the documentation) which translates the code you posted into:

StringBuilder sb = new StringBuilder();
sb.append("");
sb.append(i);
String strI = sb.toString();

在编译时。它的效率稍差（ sb.append（）最终调用 Integer.getChars（），这就是 Integer.toString（）无论如何都会完成），但它确实有效。

at compile-time. It's slightly less efficient (sb.append() ends up calling Integer.getChars(), which is what Integer.toString() would've done anyway), but it works.

回答Grodriguez的评论：**否，在这种情况下，编译器不优化空字符串 - 看：

To answer Grodriguez's comment: ** No, the compiler doesn't optimise out the empty string in this case - look:

simon@lucifer:~$ cat TestClass.java
public class TestClass {
  public static void main(String[] args) {
    int i = 5;
    String strI = "" + i;
  }
}
simon@lucifer:~$ javac TestClass.java && javap -c TestClass
Compiled from "TestClass.java"
public class TestClass extends java.lang.Object{
public TestClass();
  Code:
   0:    aload_0
   1:    invokespecial    #1; //Method java/lang/Object."<init>":()V
   4:    return

public static void main(java.lang.String[]);
  Code:
   0:    iconst_5
   1:    istore_1

初始化StringBuilder：

Initialise the StringBuilder:

   2:    new    #2; //class java/lang/StringBuilder
   5:    dup
   6:    invokespecial    #3; //Method java/lang/StringBuilder."<init>":()V

附加空字符串：

   9:    ldc    #4; //String
   11:    invokevirtual    #5; //Method java/lang/StringBuilder.append:
(Ljava/lang/String;)Ljava/lang/StringBuilder;

追加整数：

   14:    iload_1
   15:    invokevirtual    #6; //Method java/lang/StringBuilder.append:
(I)Ljava/lang/StringBuilder;

提取最终字符串：

   18:    invokevirtual    #7; //Method java/lang/StringBuilder.toString:
()Ljava/lang/String;
   21:    astore_2
   22:    return
}

有提案和正在进行的改变此行为的工作，针对JDK 9。

There's a proposal and ongoing work to change this behaviour, targetted for JDK 9.

如何从int转换为String？

相关推荐