比较两个Arrays并将Duplicates替换为第三个数组中的值

问题描述：

var array1 = ['a','b','c','d'];
var array2 = ['a','v','n','d','i','f'];

var array3 = ['1','2','3','4','5','6'];

刚开始学习Javascript，我无法弄清楚如何比较 array2 到 array1 上的那些，如果是这样的话，用 array3 $ c中的相应数组索引替换它$ c>。

Just starting to learn Javascript, I can't figure out how to compare the values of array2 to those on array1 and if so replace it with the corresponded array index from array3.

如下所示：

array2 = ['1','v','n','4','i','f'];

但是，即使索引位置不同，它也必须比较array1和array2的值这个：

But also, it has to compare the values from array1 and array2 even if the index positions are different like this:

var array1 = ['a','b','c','d'];
var array2 = ['d','v','n','a','i','f'];

感谢您的帮助

答

您可以使用哈希表并检查。如果字符串未包含在哈希表中，则为该元素设置替换值。

You could use a hash table and check against. If the string is not included in the hash table, a replacement value is set for this element.

var array1 = ['a','b','c','d'],
    array2 = ['d','v','n','a','i','f'],
    array3 = ['1','2','3','4','5','6'],
    hash = Object.create(null);

array1.forEach(function (a) {
    hash[a] = true;
});

array2.forEach(function (a, i, aa) {
    if (hash[a]) {
        aa[i] = array3[i];
    }
});

console.log(array2);

ES6， 设置

ES6 with Set

var array1 = ['a','b','c','d'],
    array2 = ['d','v','n','a','i','f'],
    array3 = ['1','2','3','4','5','6'];

array2.forEach((hash => (a, i, aa) => {
    if (hash.has(a)) {
        aa[i] = array3[i];
    }
})(new Set(array1)));

console.log(array2);

比较两个Arrays并将Duplicates替换为第三个数组中的值

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