C ++ Structs：按名称获取属性

问题描述：

我想要一个更专业的解决方案的问题。
我正在使用C ++ SOAP2解决方案。我有一个大约25个元素的Strcut定义

I'm wondring for a more professional solution for a problem. I'm working on C ++ SOAP2 solution.I have a Strcut defintion of about 25 elements

struct X { field 1; field 2; .. };

我正在填充一些地图值

Map<String,String> A

并且看起来很讨厌做这样的事n次

and it appears to be very annoying to do such thing n times

X->xx = A["aaa"]

$ b $

问题：是否可以通过名称调用struct element？
* example：to be abe to process like this：

Question : Is it possible to call struct element by name? *example: to be abe to process like this :

X->get_instance_of("xx").set(A["aaa"]);

并将其放入循环中。
*

and put it into a loop .. *

感谢，

答

C ++缺少内置的反射动态语言，所以你不能做你想要的使用他的框的能力的语言。

C++ lacks built-in reflection capabilities of more dynamic languages, so you cannot do what you would like using he out of the box capabilities of the language.

但是，如果所有成员是相同的类型，你可以使用指向成员的指针的映射和一些准备：

However, if all members are of the same type, you can do it with a map of pointers to members and a little preparation:

 // typedef for the pointer-to-member
 typedef int X::*ptr_attr;

 // Declare the map of pointers to members
 map<string,ptr_attr> mattr;
 // Add pointers to individual members one by one:
 mattr["xx"] = &X::xx;
 mattr["yy"] = &X::yy;

// Now that you have an instance of x...
 X x;
// you can access its members by pointers using the syntax below:
 x.*mattr["xx"] = A["aa"];

C ++ Structs：按名称获取属性

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