如何在Spring MVC中基于控制器和操作方法创建URL？
我正在使用Spring MVC 3.0
I am using Spring MVC 3.0
我有一个guestbook.jsp页面，我想创建一个指向GuestBookController登录方法的链接。
I have a guestbook.jsp page where I want to create a link that points to GuestBookController's login method.
这是一个简单的任务，大多数Web框架都会处理这个问题（例如Grails用g：link标签做）但我在官方SpringMVC文档中找不到任何相关文档。
This is a simple task that most web frameworks handle this (e.g grails does it with g:link tag) but I couldn't find any documentation on this in the official SpringMVC docs.
所以我摸不着头脑 - 这个功能在某些标签库中吗？框架是否暴露了它？我是否必须扩展框架才能使其正常工作？
So I am scratching my head - Is this functionality in some tag library? Does the framework expose it? Do I have to extend the framework to get this to work?
注意，我没有采用硬编码网址（这是一个明显但很弱的解决方案）而是生成它基于控制器和动作名称。
Note, I am not taking about hardcoding the url (which is an obvious but weak solution) but rather generating it based on controller and action name.
UPDATE ：
Spring MVC不提供此功能。虽然有一张JIRA票。你可以在这里投票 https://jira.springsource.org/browse/SPR-5779
简短的回答是否定的，你目前无法用Spring MVC做到这一点。
The short answer is no, you can't do this with Spring MVC currently.
这很遗憾，因为你可以在其他框架中做到这一点，包括Grails（在引擎盖下使用Spring MVC）。
It's a shame because you can do this in other frameworks including Grails (which uses Spring MVC under the hood).
参见讨论在其中包含指向添加此功能的Spring功能请求（投票支持！）
See the discussion here which includes a link to a Spring feature request to add this (vote for it!)