如何在'中仅获取文件名批处理命令而不是文件扩展名
问题描述：
使用此代码将视频上传到YouTube时，被命名的标题的文件扩展名结尾(在本例中为.mp4)
When using this code to upload video's to YouTube, the title that gets named has the file extension at the end (in this case .mp4)
for %%f in (*.mp4) do python --file="%%f" --title="%%f"
答
对(* .csv)中的%% f使用做回显"%%〜nf"
use for %%f in (*.csv) do echo "%%~nf"
有关更多信息，请对/?做一个..这是您希望看到的部分
for more info do a for /? .. this is the part that you would liek to see
In addition, substitution of FOR variable references has been enhanced.
You can now use the following optional syntax:
%~I - expands %I removing any surrounding quotes (")
%~fI - expands %I to a fully qualified path name
%~dI - expands %I to a drive letter only
%~pI - expands %I to a path only
%~nI - expands %I to a file name only
%~xI - expands %I to a file extension only
%~sI - expanded path contains short names only
%~aI - expands %I to file attributes of file
%~tI - expands %I to date/time of file
%~zI - expands %I to size of file
%~$PATH:I - searches the directories listed in the PATH
environment variable and expands %I to the
fully qualified name of the first one found.
If the environment variable name is not
defined or the file is not found by the
search, then this modifier expands to the
empty string