js - 如何根据对象数组中另一个键的值更改一个键的值

我有一个像这样的对象数组：

I have an array of objects like this:

var chartData = [{count: 0, idTag: "24"}
                 {count: 0, idTag: "25"}
                 {count: 0, idTag: "26"}]

我的代码做了一些工作并生成了一个数字（ totalValue ）。如果 totalValue 与 idTag 匹配，则其 count 会增加一个：

My code does some work and generates a number (totalValue). If totalValue matches the idTag, its count gets increased by one:

for (i=0; i<timesFlipped; i++) {
    totalValue = runTrial();
    for (j=0; j<chartData.length; j++) {
        if (chartData[j].idTag === totalValue) {
            chartData[j].count += 1;
            break;
        }
    }
}

这是一个简单的例子，但 chartData 可以容纳几十个对象，而 timesFlipped 可以是数十万次迭代。

This is a simple example, but chartData could hold a few dozen objects, and timesFlipped can be hundreds of thousands of iterations.

这是根据匹配 idTag 更改计数值的最佳方法>价值？有没有办法只使用正确的 idTag 值找到数组的索引而不迭代整个对象数组？

Is this the best way to change the count value based on matching the idTag value? Is there a way to just find the index of the array with the correct idTag value without iterating over the whole array of objects?

如果您需要更多上下文，请点击此处我正在处理的页面： http：// blue .butler.edu / ~azazman / coupling /

Here's the page I'm working on if you want more context: http://blue.butler.edu/~aazman/coupling/

更新：

感谢您的所有建议。我根据我所看到的情况形成了自己的解决方案。关于该项目的更多背景使我得到了我的解决方案：

Thanks for all the suggestions. I kinda formed my own solution based on what I saw. A bit more background about the project which led me to my solution:

• chartData $ c的长度$ c>和min idTag值是根据用户输入点击提交时计算的。


• 一次 min 和 length （因此已知max idTag），迭代初始化 chartData ：

• The length of chartData and the min idTag value are calculated based on user inputs when they click submit
• Once min and length are calculated (thus the max idTag is known), chartData is iteratively initialized:

var min = 23-5 * numNickel-numPenny; // numNickel& numPenny是用户输入

var length = 5 *（2 * numNickel + 1）+ 2 * numPenny;

var tempTag = min;

for（j = 0; j< length; j ++）{

chartData [j] = {count：0，idTag = tempTag};

tempTag ++;

}

• 由于特定于游戏规则的原因，idTag值（无论多少）都以 idTag：25 为对称中心（例如idTags = {24 ，25,26}或idTags = {20,21,22,23,24,25,26,27,28,29,30}。无论的长度为chartData ，长度将始终为奇数且 idTag：25 将始终为 [（chartData.length-1）/ 2] 'th index。

• For reasons particular to the rules of the game, the idTag values (however many there are) are symmetrically centered around idTag:25 (e.g. idTags = {24, 25, 26} or idTags = {20,21,22,23,24,25,26,27,28,29,30}. No matter the length of chartData, the length will always be odd and idTag:25 will always be the [(chartData.length-1)/2]'th index.

因此，如果idTags为 chartData {20,21,22,23,24,25,26,27,28,29,30} 以及 runTrial（）给出 totalValue = 22 ，然后 idTag：22 将始终位于索引（totalValue - min）。

Thus, if the idTags for chartData are {20,21,22,23,24,25,26,27,28,29,30} and if runTrial() gives totalValue = 22, then idTag:22 will always be at index (totalValue - min).

所以我改变了chartData的初始化以及计数增加到的方式：

So I changed the initialization of chartData and the way the count gets increased to:

for (j=0; j<length; j++) {
    chartData[j] = {count: 0};  //based on what I'm doing with chartData next, I need each index to still be an object
}

for (i=0; i<timesFlipped; i++) {
    totalValue = runTrial();
    var index = totalValue - min;
    chartData[index].count++;
}

非常感谢大家的帮助：）

So thanks all for your help :)