将str转换为python中的dict

问题描述：

我从一个进程的输出中使用subprocess.Popen（）：

I got this from a process's output using subprocess.Popen() :

    { about: 'RRDtool xport JSON output',
  meta: {
    start: 1401778440,
    step: 60,
    end: 1401778440,
    legend: [
      'rta_MIN',
      'rta_MAX',
      'rta_AVERAGE'
          ]
     },
  data: [
    [ null, null, null ],
    [ null, null, null ],
    [ null, null, null ],
    [ null, null, null ],
    [ null, null, null ],
    [ null, null, null  ]
  ]
}

似乎不是一个有效的json对我来说。
我已经使用 ast.literal_eval（）和 json.loads（），但没有运气。有人可以帮助我正确的方向吗？
提前感谢

It doesn't seem to be a valid json to me. I have used ast.literal_eval() and json.loads(), but with no luck. Can someone help me in the right direction ? Thanks in advance.

答

确实，较旧版本的 rddtool 导出ECMA脚本，而不是JSON。根据这个debian bug报告升级1.4.8应该给你适当的JSON。另请参阅项目 CHANGELOG ：

Indeed, older versions of rddtool export ECMA-script, not JSON. According to this debian bug report upgrading 1.4.8 should give you proper JSON. Also see the project CHANGELOG:

xport的JSON输出现在实际上是由它的键
正确引用的json编译。

JSON output of xport is now actually json compilant by its keys being properly quoted now.

如果您无法升级，则有两种选择：或者尝试重新格式化以引用对象密钥标识符，或使用更宽松的解析器并解析ECMA脚本对象符号。

If you cannot upgrade, you have two options here; either attempt to reformat to apply quoting the object key identifiers, or use a parser that's more lenient and parses ECMA-script object notation.

后者可以通过外部 demjson 库：

The latter can be done with the external demjson library:

>>> import demjson
>>> demjson.decode('''\
... { about: 'RRDtool xport JSON output',
...   meta: {
...     start: 1401778440,
...     step: 60,
...     end: 1401778440,
...     legend: [
...       'rta_MIN',
...       'rta_MAX',
...       'rta_AVERAGE'
...           ]
...      },
...   data: [
...     [ null, null, null ],
...     [ null, null, null ],
...     [ null, null, null ],
...     [ null, null, null ],
...     [ null, null, null ],
...     [ null, null, null  ]
...   ]
... }''')
{u'about': u'RRDtool xport JSON output', u'meta': {u'start': 1401778440, u'step': 60, u'end': 1401778440, u'legend': [u'rta_MIN', u'rta_MAX', u'rta_AVERAGE']}, u'data': [[None, None, None], [None, None, None], [None, None, None], [None, None, None], [None, None, None], [None, None, None]]}

可以做你唱一个正则表达式我将假设所有标识符都在新行上，或者直接在开始之后 {卷曲括号。列表中的单引号必须更改为双引号;只有在值中没有嵌入单引号的情况下，这才有效：

Repairing can be done using a regular expression; I am going to assume that all identifiers are on a new line or directly after the opening { curly brace. Single quotes in the list will have to be changed to double quotes; this will only work if there are no embedded single quotes in the values too:

import re
import json

yourtext = re.sub(r'(?:^|(?<={))\s*(\w+)(?=:)', r' "\1"', yourtext, flags=re.M)
yourtext = re.sub(r"'", r'"', yourtext)
data = json.loads(yourtext)

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