使用Android从URL获取JSON数据?

问题描述：

我正在尝试通过使用用户名和密码解析登录URL来获取JSON数据.我已经尝试通过使用下面的代码，但是我没有得到任何回应.请帮助我.

I am trying to get JSON data by parsing login url with username and password. I have tried by using below code but I can't get any responses. Please help me.

我正在使用HTTP流程和API级别23.

I am using HTTP Process and API level 23.

我需要解析我的URL并获得以下响应

I need to parse my URL and get below Response

{
    "response":{
                "Team":"A",
                "Name":"Sonu",
                "Class":"First",
              },
                "Result":"Good",
}

在我的代码下面:

public class LoginActivity extends Activity {

    JSONParser jsonparser = new JSONParser();
    TextView tv;
    String ab;
    JSONObject jobj = null;
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.login);

        new retrievedata().execute();

    }

    class retrievedata extends AsyncTask<String, String, String>{

        @Override
        protected String doInBackground(String... arg0) {
            // TODO Auto-generated method stub
            jobj = jsonparser.makeHttpRequest("http://myurlhere.com");

            // check your log for json response
            Log.d("Login attempt", jobj.toString());

            try {
                ab = jobj.getString("title");
            } catch (JSONException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
            return ab;
        }
        protected void onPostExecute(String ab){

            tv.setText(ab);
        }

    }

}

答

获取JSON的简便方法，尤其是对于 Android SDK 23 :

Easy way to get JSON especially for Android SDK 23:

public class MainActivity extends AppCompatActivity {

Button btnHit;
TextView txtJson;
ProgressDialog pd;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    btnHit = (Button) findViewById(R.id.btnHit);
    txtJson = (TextView) findViewById(R.id.tvJsonItem);

    btnHit.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            new JsonTask().execute("Url address here");
        }
    });


}


private class JsonTask extends AsyncTask<String, String, String> {

    protected void onPreExecute() {
        super.onPreExecute();

        pd = new ProgressDialog(MainActivity.this);
        pd.setMessage("Please wait");
        pd.setCancelable(false);
        pd.show();
    }

    protected String doInBackground(String... params) {


        HttpURLConnection connection = null;
        BufferedReader reader = null;

        try {
            URL url = new URL(params[0]);
            connection = (HttpURLConnection) url.openConnection();
            connection.connect();


            InputStream stream = connection.getInputStream();

            reader = new BufferedReader(new InputStreamReader(stream));

            StringBuffer buffer = new StringBuffer();
            String line = "";

            while ((line = reader.readLine()) != null) {
                buffer.append(line+"\n");
                Log.d("Response: ", "> " + line);   //here u ll get whole response...... :-) 

            }

            return buffer.toString();


        } catch (MalformedURLException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        } finally {
            if (connection != null) {
                connection.disconnect();
            }
            try {
                if (reader != null) {
                    reader.close();
                }
            } catch (IOException e) {
                e.printStackTrace();
            }
        }
        return null;
    }

    @Override
    protected void onPostExecute(String result) {
        super.onPostExecute(result);
        if (pd.isShowing()){
            pd.dismiss();
        }
        txtJson.setText(result);
    }
}
}

使用Android从URL获取JSON数据?

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