如何在Golang中编写一个以多种类型为参数的函数？

问题描述：

I am trying to write a function in Golang which will serialize a map and a slice (convert it to a string). I want it to take one parameter but I am unsure of how to make it accept a map and a slice only. I know I can use something like the following function but beyond this point I am confused. I am still trying to wrap my head around interfaces.

func Serialize(data interface{}) string {
    return ""
}

It is preferred if I don't need to create my own struct for it. An explanation of how I could allow this Serialize function to accept maps and structs would be hugely appreciated.

我正在尝试用Golang写一个函数，该函数将序列化地图和切片（将其转换为字符串）。我希望它采用一个参数，但是我不确定如何使它仅接受地图和切片。我知道我可以使用类似以下功能的东西，但在这一点上我感到困惑。我仍在尝试绕过接口。 p>

  func Serialize（data interface {}）string {
 return“” 
} 
  code>  
 
 如果我不需要为其创建自己的结构，则它是首选。 非常感谢我对如何允许此Serialize函数接受映射和结构的解释。 p> 
  div>

答

You could simply use fmt.Sprintf for this:

type foo struct {
    bar  string
    more int
}

func main() {
    s := []string{"a", "b", "c"}
    fmt.Println(Serialize(s))

    m := map[string]string{"a": "a", "b": "b"}
    fmt.Println(Serialize(m))

    t := foo{"x", 7}    
    fmt.Println(Serialize(t))
}

func Serialize(data interface{}) string {
    str := fmt.Sprintf("%v", data)
    return str
}

This will print:

[a b c]

map[b:b a:a]

{x 7}

You can easily trim off the {}, [] and map[] if desired/required with strings.TrimSuffix and strings.TrimPrefix

如何在Golang中编写一个以多种类型为参数的函数？

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