python:从html获取图像链接

问题描述：

来自这样的 html/rss 片段

From a html/rss snippet like this

[...]<div class="..." style="..."></div><p><a href="..."
<img alt="" heightt="" src="http://link.to/image"
width="" /></a><span style="">[...]

我想获取图像源链接http://link.to/image.jpg".我怎么能在python中做到这一点?谢谢.

I want to get the image src link "http://link.to/image.jpg". How can I do this in python? Thanks.

答

lxml 是工作的工具.

lxml is the tool for the job.

从网页中抓取所有图像就像这样简单:

To scrape all the images from a webpage would be as simple as this:

import lxml.html

tree = lxml.html.parse("http://example.com")
images = tree.xpath("//img/@src")

print images

给予:

['/_img/iana-logo-pageheader.png', '/_img/icann-logo-micro.png']

如果是 RSS 提要，您需要使用 lxml.etree 解析它.

If it was an RSS feed, you'd want to parse it with lxml.etree.