如何在Python中将列表分为两个唯一列表?
问题描述:
我有一个列表如下:
listt = ['a','b','c','d','e','f','g','h', 'i','j','k','l','m','n','o']
15个成员。
Hi I have a list as following: listt = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o'] 15 members.
我想将其转换为3个列表,我使用了有效的代码,但我想要唯一的列表。这会给我3个具有共同成员的列表。
I want to turn it into 3 lists, I used this code it worked but I want unique lists. this give me 3 lists that have mutual members.
import random
listt = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o']
print(random.sample(listt,5))
print(random.sample(listt,5))
print(random.sample(listt,5))
答
尝试一下:
from random import shuffle
def randomise():
listt = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o']
shuffle(listt)
return listt[:5], listt[5:10], listt[10:]
print(randomise())
这将进行打印(例如,由于它是随机的):
This will print (for example, since it is random):
(['i', 'k', 'c', 'b', 'a'], ['d', 'j', 'h', 'n', 'f'], ['e', 'l', 'o', 'g', 'm'])