显示框，如果单选按钮使用jQuery检查

问题描述：

我有以下的code：

    <fieldset>
        <legend>Do you currently have SolidWorks</legend>

        <ul>
            <li><label for=""><input type="radio" name="solidworks" value="Yes" id="rdYes" /> Yes</label></li>
            <li><label for=""><input type="radio" name="solidworks" value="No" id="rdNo" /> No</label></li>
        </ul>
    </fieldset>

    <fieldset id="boxReseller" style="display:none;">
        <legend>Who is your SolidWorks reseller?</legend>
        <ul>
            <li><label for=""><input type="radio" name="reseller" value="Cad Connect" /> Cad Connect</label></li>
            <li><label for=""><input type="radio" name="reseller" value="Cadtek" /> Cadtek</label></li>
            <li><label for=""><input type="radio" name="reseller" value="CCSL" /> CCSL</label></li>
            <li><label for=""><input type="radio" name="reseller" value="Innova" /> Innova</label></li>
            <li><label for=""><input type="radio" name="reseller" value="NT CAD/CAM" /> NT CAD/CAM</label></li>
            <li><label for=""><input type="radio" name="reseller" value="Solid Engineer" /> Solid Engineer</label></li>
            <li><label for=""><input type="radio" name="reseller" value="Solid Solutions Ireland" /> Solid Solutions Ireland</label></li>
            <li><label for=""><input type="radio" name="reseller" value="Solid Solutions Management" /> Solid Solutions Management</label></li>
            <li><label for=""><input type="radio" name="reseller" value="TMS Scotland" /> TMS Scotland</label></li>
        </ul>

    </fieldset>

我想要做的是默认隐藏第二字段集，如果一个人选择是，然后将出现的框，如果他们选择否或不选择是那么框将再次隐藏。

What I want to do is hide the second fieldset by default and if a person chooses Yes then the box will appear, and if they choose No or Yes is not selected then the box will hide again.

谁能帮助？谢谢你。

答

参考尼克Craver - 很好的解决方案，虽然它是如下

Ref Nick Craver - Nice solution although it is more felxaible as below

  $("input[name='solidworks']").change(function() {
    $("#boxReseller").toggle();
 });
$("input[name='solidworks']:checked").change(); //trigger correct state onload

通过让拨动作为通配符（未定义任何术语你preFER），我发现它的工作效率更高。尼斯虽然，谢谢:)

By leaving the toggle as a wild card (undefined whichever terminology you prefer) I found it worked more efficiently. Nice though, thanks :)

显示框，如果单选按钮使用jQuery检查

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