MySQL中具有相似ID的行的列的总和

问题描述：

我在称为购买"的表中有3列:

I have 3 columns in a table called "purchases":

id         amount         price
2          2              21
2          5              9
3          8              5

我想对所有具有相似ID的行进行分组，并得到以下结果:

I want to group all rows with similar IDs and have this array as a result:

array([0] => [id => 2, total => 87 (because 2*21+5*9=87)], [1] => [id => 3, total => 40 (because 8*5=40)])

作为具有相同ID的行的总计SUM(金额*价格).

as total accounts for SUM(amount*price) for rows with similar IDs.

我尝试使用

SELECT id, SUM(p.price*p.amount) total FROM purchases p GROUP by p.id

，但效果不佳(即无法实现我想要的功能，这就是我上面写的内容). 关于如何在mysql中执行此操作的任何想法?

but it doesn't work well (i.e. it doesn't achieve what I want, which is what I wrote above). Any ideas on how to do this in mysql?

查询返回的示例:

    id         amount         price
    2          3              89
    2          3              19

    SELECT id, SUM(p.price*p.amount) total FROM purchases p GROUP by p.id

==> [id => 2, total => 183]

答

SELECT
id, 
SUM(amount*price) AS total
FROM mytable
GROUP BY id

数据:

| id | amount | price |
|----|--------|-------|
| 2  | 3      | 19    |
| 2  | 3      | 89    |
| 3  | 203    | 1     |

结果:

id  total
2   324
3   203

MySQL中具有相似ID的行的列的总和

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