Python:如何使用用户输入来关闭或继续while循环

问题描述：

我是python的新手，并且仍在尝试弄清楚基础知识.我一直在网上寻找答案，但似乎没有任何解决方案适合我.我不知道我是否缺少一些小东西，或者我的总体结构是错误的.我的代码的计算部分按预期工作.

I am new to python, and still trying to figure out the basics. I've looked for an answer online, but no solutions seem to work for me. I don't know if I'm missing something small, or my total structure is wrong. The calculation portion of my code works like it's supposed to.

我的问题是，我不知道如何要求用户输入是或否，结果是:

My problem is, I can't figure out how to ask the user to input yes or no resulting in:

(是的答案将重新启动循环，以便用户可以尝试其他计算)

(the answer YES restarting the loop so the user can try another calculation)

(答案为不关闭循环/结束程序")

(the answer NO closing the loop/ending the program)

请让我知道您的建议！

    play = True

while play:

    hours = float(input("Please enter the number of hours worked this week: "))
    rate = float(input("Please enter your hourly rate of pay: "))

    #if less than 40 hrs
    if hours <= 40:
        pay = hours * rate
        print "Your pay for this week is",pay

    #overtime 54hrs or less   
    elif hours > 40 < 54:
        timeandhalf = rate * 1.5
        pay = (40 * hours * rate) + ((hours - 40) * timeandhalf)
        print "Your pay for this week is",pay 

    #doubletime more than 54hrs        
    elif hours > 54:
        timeandhalf = rate * 1.5
        doubletime = rate * 2
        pay = (40 * hours * rate) + ((hours - 40) * timeandhalf) + ((hours - 54) * doubletime)
        print "Your pay for this week is",pay    


    answer = (input("Would you like to try again?: "))
    if str(answer) == 'yes':
        play = True
    else:
        play = False

答

您正在使用Python2.x. input() 尝试将输入作为有效的运行Python表达式.输入字符串时，它将尝试在名称空间中查找它，如果找不到，则会引发错误:

You are use Python 2.x. input() tries to run the input as a valid Python expression. When you enter a string, it tries to look for it in the namespace, if it is not found it throws an error:

NameError:名称'yes'未定义

NameError: name 'yes' is not defined

您不应使用input来接收未经过滤的用户输入，这很危险.而是使用 raw_input() 返回一个字符串:

You should not use input to receive unfiltered user input, it can be dangerous. Instead, use raw_input() that returns a string:

play = True

while play:

    hours = float(raw_input("Please enter the number of hours worked this week: "))
    rate = float(raw_input("Please enter your hourly rate of pay: "))

    #if less than 40 hrs
    if hours <= 40:
        pay = hours * rate
        print "Your pay for this week is",pay

    #overtime 54hrs or less   
    elif hours > 40 < 54:
        timeandhalf = rate * 1.5
        pay = (40 * hours * rate) + ((hours - 40) * timeandhalf)
        print "Your pay for this week is",pay 

    #doubletime more than 54hrs        
    elif hours > 54:
        timeandhalf = rate * 1.5
        doubletime = rate * 2
        pay = (40 * hours * rate) + ((hours - 40) * timeandhalf) + ((hours - 54) * doubletime)
        print "Your pay for this week is",pay    

    answer = raw_input("Would you like to try again?: ").lower()
    while True:
        if answer == 'yes':
            play = True
            break
        elif answer == 'no':
            play = False
            break
        else:
            answer = raw_input('Incorrect option. Type "YES" to try again or "NO" to leave": ').lower()

Python:如何使用用户输入来关闭或继续while循环

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