C++二进制翻转实例分析

本文实例讲述了C++二进制翻转的方法，将常用的几种解决方法罗列出来供大家比较选择。具体如下：

首先来看看一个相对笨拙的算法：

#include <iostream>

using namespace std;

void printBinary(unsigned char str, int size = 1)
{
 int flag = 0x01;
 for (int i = 0; i < size; i++)
 {
 for (int i = 0; i < 8; i++)
 {
  if (str & (0x01 << (7 - i)))
  cout << "1";
  else
  cout << "0";
 }
 cout << endl;;
 }
}

unsigned char mySwap(unsigned char data)
{
 unsigned char flag = 0x01;
 for (int i = 0, j = 7; i < j; i++, j--)
 {
 int right = data & (0x01 << i);
 int left = data & (0x01 << j);
 data &= ~(0x01 << j);
 data &= ~(0x01 << i);
 int dist = j - i;
 data |= (right << dist);
 data |= (left >> dist);
 }
 return data;
}

void main(void)
{
 char source=0x07;
 int i;
 printBinary(source, 1);
 unsigned char result = mySwap(source);
 printBinary(result);
}

下面这个翻转程序相对上面实例而言简洁高效：

unsigned char swapBinary(unsigned char data)
{
 int sign = 1;
 unsigned char result = 0;
 for (int i = 0; i <= 7; i++)
 {
 result += ((data & (sign << i)) >> i) << (7 - i);
 }

 return result;
}

下面这个反转程序比较容易理解：

unsigned char swapBinary2(unsigned char data)
{
 data=(( data & 0xf0) >> 4) | ((data & 0x0f) << 4); 
 data=((data & 0xCC) >> 2) | ((data & 0x33) << 2); 
 data=((data & 0xAA) >> 1) | ((data & 0x55) << 1); 
 return data; 
}

最后这个超牛的反转程序简直碉堡了。。。

unsigned char codeTable[16]={0x00, 0x08, 0x04, 0x0c, 0x02, 0x0a, 0x06, 0x0e, 0x01, 0x09, 0x05, 0x0d, 0x03, 0x0b, 0x07, 0x0f}; 

unsigned char swapBinary3(unsigned char data) 
{ 
 return ((codeTable[data >> 4]) | (codeTable[data & 0x0f] << 4));
}

希望本文所述对大家C++程序算法设计的学习有所帮助。

C++二进制翻转实例分析

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