如何创建从字节[]在C#中的bmp文件
我在TCP Client.The阵列接收一个byte []数组包含一个24位RGB位图file.How创建位图文件给定宽度,高度和数据吗?
I have a byte[] array received in TCP Client.The array contains a 24-bit RGB Bitmap file.How to create that bitmap file with given Width ,Height and data?
在C ++中我使用这个
In C++ I use this
int WriteBitmapFile(const char *filename, int width, int height, unsigned char *imageData)
{
FILE *filePtr; // file pointer
BITMAPFILEHEADER bitmapFileHeader; // bitmap file header
BITMAPINFOHEADER bitmapInfoHeader; // bitmap info header
DWORD imageIdx; // used for swapping RGB->BGR
unsigned char tempRGB; // used for swapping
// open file for writing binary mode
filePtr = fopen(filename, "wb");
if (!filePtr)
return 0;
// define the bitmap file header
bitmapFileHeader.bfSize = sizeof(BITMAPFILEHEADER);
bitmapFileHeader.bfType = 0x4D42;
bitmapFileHeader.bfReserved1 = 0;
bitmapFileHeader.bfReserved2 = 0;
bitmapFileHeader.bfOffBits = sizeof(BITMAPFILEHEADER) + sizeof(BITMAPINFOHEADER);
// define the bitmap information header
bitmapInfoHeader.biSize = sizeof(BITMAPINFOHEADER);
bitmapInfoHeader.biPlanes = 1;
bitmapInfoHeader.biBitCount = 32; // 24-bit
bitmapInfoHeader.biCompression = BI_RGB; // no compression
bitmapInfoHeader.biSizeImage = width * abs(height) * 4; // width * height * (RGB bytes)
bitmapInfoHeader.biXPelsPerMeter = 0;
bitmapInfoHeader.biYPelsPerMeter = 0;
bitmapInfoHeader.biClrUsed = 0;
bitmapInfoHeader.biClrImportant = 0;
bitmapInfoHeader.biWidth = width; // bitmap width
bitmapInfoHeader.biHeight = height; // bitmap height
// switch the image data from RGB to BGR
for(imageIdx = 0; imageIdx < bitmapInfoHeader.biSizeImage; imageIdx+=4)
{
tempRGB = imageData[imageIdx];
imageData[imageIdx] = imageData[imageIdx + 2];
imageData[imageIdx + 2] = tempRGB;
}
// write the bitmap file header
fwrite(&bitmapFileHeader, 1, sizeof(BITMAPFILEHEADER), filePtr);
// write the bitmap info header
fwrite(&bitmapInfoHeader, 1, sizeof(BITMAPINFOHEADER), filePtr);
// write the image data
fwrite(imageData, 1, bitmapInfoHeader.biSizeImage, filePtr);
// close our file
fclose(filePtr);
// Success
return 1;
}
我
怎么能这样做,在C#?
How could I do that in C#?
如果数组实际上包含位图文件,那么你可以字节保存为一个文件:
If the array actually contains a bitmap file, then you can just save the bytes as a file:
File.WriteAllBytes(fileName, imageData);
如果该数组只包含原始像素数据,可以使用数据创建一个位图对象:
If the array contains only raw pixel data, you can create a Bitmap object using the data:
unsafe {
fixed (byte* ptr = imageData) {
using (Bitmap image = new Bitmap(width, height, stride, PixelFormat.Format24bppRgb, new IntPtr(ptr))) {
image.Save(fileName);
}
}
}
的步幅
值是扫描线之间的字节数。如果在扫描行之间没有空白,它的宽* 3
为和24bpp格式。
The stride
value is the number of bytes between the scan lines. If there is no padding between the scan lines, it's width * 3
for a 24bpp format.
此方法使用阵列中的数据而不在存储器中的整个图象的另一副本(这就是为什么它需要的步幅值)。
This method uses the data in the array without creating another copy of the entire image in memory (which is why it needs the stride value).
如果位图数据被存储颠倒的阵列中,在步幅
值应该是负的,和指针应该在存储器中的最后的扫描线的开始( PTR +步速*(高 - 1)。
)
If the bitmap data is stored upside down in the array, the stride
value should be negative, and the pointer should be the start of the last scan line in memory (ptr + stride * (height - 1)
).