函数是否有可能在Golang中赤裸裸地返回错误？

问题描述：

I have a set of constructs like this:

func LoginUser(w http.ResponseWriter, req *http.Request) {
    // do some check here 
    if err != nil {
        ReturnErrorResponse(w, errors.LoginError)
        return
    }

    // do some check here 
    if err != nil {
        ReturnErrorResponse(w, errors.BannedUserError)
        return
    }

    //success
}

I wonder if it's possible to get rid of these returns and somehow embed them into the ReturnErrorResponse function?

So, if an error happens, I return a JSONified response with error code and make a naked return.

我有一组这样的构造： p>

  func  LoginUser（w http.ResponseWriter，req * http.Request）{
 //在这里做一些检查
 err！= nil {
 ReturnErrorResponse（w，errors.LoginError）
 return 
} 
 
  //在这里做一些检查
如果错误！= nil {
 ReturnErrorResponse（w，errors.BannedUserError）
 return 
} 
 
 //成功
} 
  code>  pre>  
 
 我想知道是否有可能摆脱这些 return  code>并将它们嵌入到 ReturnErrorResponse  code>函数中？ p> 
 
  
因此，如果发生错误，我将返回带有错误代码的JSON化响应并进行裸返回。 p> 
  div>

答

It's possible by calling panic() e.g. in your ReturnErrorResponse() function (after sending back the error), but it's neither idiomatic nor efficient.

Using panic() would of course require to call recover() in a deferred function, which could be done in one place, e.g. in a "master" handler passed to http.ListenAndServe().

What you're doing is the proper way. Do not use panic() for this.

函数是否有可能在Golang中赤裸裸地返回错误？

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