在C ++中初始化抽象基类的子类数组

问题描述：

我在C ++中有一个抽象基类，需要创建一个数组来存储作为其子类的对象.由于数组的每个成员都必须具有相同的大小，因此我使用了指向子类的指针.目前，我正在像这样声明和初始化我的数组:

I have an abstract base class in C++ and need to create an array to store objects which are subclasses of it. I use pointers to the subclasses since each member of the array needs to be of the same size. Currently I am declaring and initializing my array like this:

BaseClass *array[];
...
array =
{
    &SubClass1(...),
    &SubClass2(...),
    ...
    &SubClass3(...)
};

当我尝试编译时，这给了我以下信息:

This is giving me the following when I try to compile:

warning: taking address of temporary
error: too many initializers for ‘BaseClass* [0]’

执行此操作的正确方法是什么?

What's the proper way of doing this?

答

与您在& SubClass1()中所做的操作相同，并且不带临时地址...)，.诸如此类的东西:

On the same line and not taking the address of the temporary as you're doing in &SubClass1(...),. Something, like:

BaseClass *array [] = { new SubClass(...), new SubClass2(...), .... };

但是这种设计有点像不知道如何做工厂.

But this design smells a bit like not knowing how to do a factory.

由于您没有使用 std :: shared_ptr 或 std :: unique_ptr 来管理指针，所以请不要忘记删除！(感谢@dasblinkenlight)

As you're not using std::shared_ptr or std::unique_ptr to manage your pointer, do not forget to delete them ! (thanks @dasblinkenlight)

在C ++中初始化抽象基类的子类数组

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