Java：当单词之间有可变数量的空格时，按空格分割字符串？

问题描述：

我有以下内容：

String string = "1-50  of 500+";
String[] stringArray = string.split(" ");

打印出这个数组中的所有元素给出了以下内容：

Printing out all the elements in this array gives me the following:

Element 1: 1-50
Element 2:  of 500+

如何通过要求单词之间至少有一个空格来分割元素？

How can I get it to split elements by the requirement that there is at least one whitespace between the words?

其他单词，我希望我的元素是：

In other words, I want my elements to be:

Element 1: 1-50
Element 2: of
Element 3: 500+

答

使用 \\\\ + 即使它们更多，也要拆分空格。

Use \\s+ to split on spaces even if they are more.

String string = "1-50  of 500+";
String[] stringArray = string.split("\\s+");

for (String str : stringArray)
{
    System.out.println(str);
}

编辑：

如果您还要拆分选项卡，请将正则表达式更改为 \\\\ + | \\t + 并且它还检测空格和制表符。

If you also want to split on tabs, change the regex to \\s+|\\t+ and it detects both spaces and tabs as well.