mongodb/mongoose findMany - 查找 ID 列在数组中的所有文档

问题描述:

我有一个 _id 数组,我想相应地获取所有文档,最好的方法是什么?

I have an array of _ids and I want to get all docs accordingly, what's the best way to do it ?

类似……

// doesn't work ... of course ...

model.find({
    '_id' : [
        '4ed3ede8844f0f351100000c',
        '4ed3f117a844e0471100000d', 
        '4ed3f18132f50c491100000e'
    ]
}, function(err, docs){
    console.log(docs);
});

该数组可能包含数百个 _id.

The array might contain hundreds of _ids.

mongoose 中的 find 函数是对 mongoDB 的完整查询.这意味着您可以使用方便的 mongoDB $in 子句,它的工作方式与 SQL 版本相同.

The find function in mongoose is a full query to mongoDB. This means you can use the handy mongoDB $in clause, which works just like the SQL version of the same.

model.find({
    '_id': { $in: [
        mongoose.Types.ObjectId('4ed3ede8844f0f351100000c'),
        mongoose.Types.ObjectId('4ed3f117a844e0471100000d'), 
        mongoose.Types.ObjectId('4ed3f18132f50c491100000e')
    ]}
}, function(err, docs){
     console.log(docs);
});

即使对于包含数万个 id 的数组,这种方法也能很好地工作.(请参阅有效确定记录的所有者)

This method will work well even for arrays containing tens of thousands of ids. (See Efficiently determine the owner of a record)

我建议任何使用 mongoDB 的人通读 高级查询 优秀官方 mongoDB 文档 部分>

I would recommend that anybody working with mongoDB read through the Advanced Queries section of the excellent Official mongoDB Docs