您的位置: 首页  >  技术问答  >  麻烦再问，更好的解释...请帮助我:(

麻烦再问，更好的解释...请帮助我:(

分类: 技术问答 • 2022-07-13 21:30:52
问题描述：

我问了这个问题，但是编码人员似乎不知道我想要什么，因为这很难解释.它使我发疯，所以病了要给她开枪.

好的，我的应用程序要求用户输入较长的安装ID:

50个十进制数字
分为每组六个数字，如
002666-077894-484890-114573-XXXXXX-XXXXXX-XXXXXX-XXXXXX-XX


那么我们有:

删除校验位将产生41位十进制数. A
此长度的十进制数字大致对应于136位二进制
数字.实际上，41位数字只是
的十进制编码 这样的136位多精度整数，存储在little
endian字节顺序作为字节数组.因此，上述安装ID
也可以表示为17个字节的序列，如
0xXX 0xXX 0xXX 0xXX 0xXX 0xXX 0xXX 0xXX
0x94 0xAA 0x46 0xD6 0x0F 0xBD 0x2C 0xC8
0x00


所以我的问题是这样的:

如何将安装ID字符串("xxxxxx-xxxxxx-等")获取到上面的字节数组中，该字节数组表示数字的十进制编码.

这就是我想做的，以便我可以尝试使自己变得很清楚.

我想要一个固定长度的字节数组，例如:

0xXX 0xXX 0xXX 0xXX 0xXX 0xXX 0xXX 0xXX
0x94 0xAA 0x46 0xD6 0x0F 0xBD 0x2C 0xC8
0x00

然后，我将使用固定长度的密钥对字节数组进行加密.

然后，我想用字符串将字节数组表示为其数字表示形式:

002666-077894-484890-114573-XXXXXX-XXXXXX-XXXXXX-XXXXXX-XX

我真的希望这会有所帮助.
再次谢谢你.
Steve

I have asked this question but but coders didnt seem to know what i wanted as it was hard to explain. It is driving me insane so ill give it anouther shot.

OK, My application asks the user to enter a long installation ID:

50 decimal digits that are
divided into groups of six digits each, as in
002666-077894-484890-114573-XXXXXX-XXXXXX-XXXXXX-XXXXXX-XX


then we have:

Removing the check digits results in a 41-digit decimal number. A
decimal number of this length roughly corresponds to a 136-bit binary
number. In fact, the 41-digit number is just the decimal encoding of
such a 136-bit multi-precision integer, which is stored in little
endian byte order as a byte array. Hence, the above Installation ID
can also be represented as a sequence of 17 bytes as in
0xXX 0xXX 0xXX 0xXX 0xXX 0xXX 0xXX 0xXX
0x94 0xAA 0x46 0xD6 0x0F 0xBD 0x2C 0xC8
0x00


So my question is this:

How do i get the installation id string ("xxxxxx-xxxxxx- etc") into a byte array above, that represents the decimal encoding of the number.

This is what i want to do, just so i can try and make myself very clear.

I want a fixed length byte array, like:

0xXX 0xXX 0xXX 0xXX 0xXX 0xXX 0xXX 0xXX
0x94 0xAA 0x46 0xD6 0x0F 0xBD 0x2C 0xC8
0x00

I will then encrypt the byte array with a fixed length key.

I then want to represent the byte array as its number representation, in a string:

002666-077894-484890-114573-XXXXXX-XXXXXX-XXXXXX-XXXXXX-XX

I realy hope this helps.
Thank you again.
Steve

答

尝试一下；

Try this;

string startValue = "456345-007876-343234-765676-543456-566565-321234-345654".Replace("-", "");
char[] indivualNumbers = startValue.ToCharArray();
byte[] arrayValue = new byte[indivualNumbers.Length];
int numberCounter = 0;
foreach (char numberValue in indivualNumbers)
{
   arrayValue[numberCounter] = (byte)Convert.ToInt32(numberValue);
   ++numberCounter;
}



这是我在上一个问题中提供的第二个选项的最终结果.



This is the end result of the second option I gave in your previous question.


两个单词二进制数学".

您需要将字符串从最小有效数字移到最高有效.

将当前字符串值存储在一个字节中，调用此currentValue.
乘数再加上一个byte [].
和另一个byte []作为结果.

开始于；
Two words "Binary Math".

You need to walk the string from lest significant digit to most significant.

store the current string value in a byte call this currentValue.
have another byte[] with the multiplier.
and another byte[] for the result.

start off with;
byte[] multiplier = new byte[1];
multiplier[0] = 1;
byte currentValue = null; 
byte[] result = new byte[1];
result[0] = 0;

foreach(char charValue in "5634007873432376567543455665632123345654".toCharArray().Reverse())
{
  currentValue = (byte)Convert.ToInt16(charValue ); 

  //Next two lines require binary math routines
  result = result + (currentValue * multiplier);
  multiplier = multiplier  * 10;
}



显然，这是伪代码版本，因为字节数组，乘数和结果随着存储在它们中的数字变大而需要增加.



obviously this is the pseudocode version as the byte arrays, multiplier and result, will need to grow as the number stored in them gets larger.


再次感谢，但这不是我想要的. br/>
您的答案产生48个字节，正如我在上面试图解释的那样，该字符串的十进制表示形式应该为17个字节长.

我基本上是想在c#中重现以下内容


http://www.licenturion.com/xp/fully-licensed-wpa.txt

希望能有所帮助，因为我现在已经空白了，我也不会在意，但我之前找到了答案，无法再次得到它.

谢谢
史蒂夫
Thanks again but this is not what i want.

Your answer produces 48 bytes and as i am trying to explain above, the decimal representation of that string is supposed to be 17 bytes long.

I am basicaly trying to reproduce the following in c#


http://www.licenturion.com/xp/fully-licensed-wpa.txt

Hope that helps as i have now drew a blank, and i wouldnt care but i found the answer before and cant get it again.

Thank you
Steve


相关推荐