手机号码验证安卓

问题描述：

如何检查电话号码是否有效?最大长度为13(包括前面的字符+).

How do I check if a phone number is valid or not? It is up to length 13 (including character + in front).

我该怎么做?

我试过了:

String regexStr = "^[0-9]$";

String number=entered_number.getText().toString();  

if(entered_number.getText().toString().length()<10 || number.length()>13 || number.matches(regexStr)==false  ) {
    Toast.makeText(MyDialog.this,"Please enter "+"
"+" valid phone number",Toast.LENGTH_SHORT).show();
    // am_checked=0;
}`

我也试过这个:

public boolean isValidPhoneNumber(String number)
{
     for (char c : number.toCharArray())
     {
         if (!VALID_CHARS.contains(c))
         {
            return false;
         }
     }
     // All characters were valid
     return true;
}

两者都不起作用.

输入类型:+号被接受，0-9个数字，长度b/w 10-13，不能接受其他字符

答

鉴于您指定的规则:

长度不超过 13，包括字符 + 前面.

upto length 13 and including character + infront.

(并在您的代码中加入最小长度 10)

(and also incorporating the min length of 10 in your code)

你会想要一个看起来像这样的正则表达式:

You're going to want a regex that looks like this:

^+[0-9]{10,13}$

使用正则表达式中编码的最小和最大长度，您可以从 if() 块中删除这些条件.

With the min and max lengths encoded in the regex, you can drop those conditions from your if() block.

题外话:我建议 10 - 13 的范围对于国际电话号码字段来说太有限了；你几乎肯定会找到比这更长和更短的有效数字.为了安全起见，我建议范围在 8 - 20 之间.

Off topic: I'd suggest that a range of 10 - 13 is too limiting for an international phone number field; you're almost certain to find valid numbers that are both longer and shorter than this. I'd suggest a range of 8 - 20 to be safe.

OP 表示由于转义序列，上述正则表达式不起作用.不知道为什么，但另一种选择是:

OP states the above regex doesn't work due to the escape sequence. Not sure why, but an alternative would be:

^[+][0-9]{10,13}$

OP 现在补充说 + 符号应该是可选的.在这种情况下，正则表达式需要在 + 后面加上一个问号，所以上面的例子现在看起来像这样:

OP now adds that the + sign should be optional. In this case, the regex needs a question mark after the +, so the example above would now look like this:

^[+]?[0-9]{10,13}$

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